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kirill115 [55]
3 years ago
8

Match the function with the graph. Please help it is TIMED.

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
D cause +2 means shift left and +3 means shift up
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A chemist needs 130 milliliters of a 47% solution but has only 35% and 87% solutions available. Find how many milliliters of eac
choli [55]

Answer: Amount of 35% solution required = 100 milliliters

Amount of 87% solution required  = 30 milliliters

Step-by-step explanation:

Given: Total solution required =  130 milliliters

Let x = Amount of 35% solution (in milliliters).

Then, Amount of 87% solution required = 130 - x

As per given,

Concentration = 0.35x +0.87(130-x)=0.47(130)

0.35x +113.1-0.87x=61.1\\\\\Rightarrow\ -0.87x+0.35x=61.1-113.1\\\\\Rightarrow\ -0.52 x= -52\\\\\Rightarrow\ x=\dfrac{52}{0.52}=100

Hence, Amount of 35% solution required = 100 milliliters

Amount of 87% solution required  = 130-100 milliliters =30 milliliters

3 0
3 years ago
A jacket is priced at $90.00 but has a discount of 40%. what is the sale price?<br> show work!
alexdok [17]

Answer:

$36

Step-by-step explanation:

90*0.40=36

40%=0.40

8 0
4 years ago
Read 2 more answers
Evaluate the expression.<br> -6+3(-3+7).
lesantik [10]

Answer:

answer for this question is 6

3 0
3 years ago
Read 2 more answers
(THIS IS A TEST I NEED HELP)
Leya [2.2K]

Answer:

Option (B)

Step-by-step explanation:

Length of PR = 4

RS = 4

QS = 4

For the length of PT,

PT² = RT² + PR² [Since, PT is the diagonal of rectangle PRT]

PT² = QS² + PR² [Since, RT ≅ QS]

PT² = 4² + 7²

PT² = 16 + 49

PT² = 65

Now for the length of PQ,

PQ² = QT² + PT²

PQ² = RS² + PT² [Since, QT ≅ RS]

PQ² = 4² + 65

PQ² = 16 + 65

PQ = √81

PQ = 9

Therefore, length of diagonal PQ is 9 units.

Option (B) will be the answer.

4 0
3 years ago
Find all solutions to the equation. 2sin theta - squareroot 3 = 0
Xelga [282]

Answer:

\theta =2mπ + π/3 for m ∈ Z.

Step-by-step explanation:

Given the equation 2sin\theta - \sqrt{3} = 0, we are to find all the values of \theta that satisfies the equation.

2sin\theta - \sqrt{3} = 0\\\\2sin\theta = \sqrt{3} \\\\sin\theta = \sqrt{3}/2 \\\\\theta = sin{-1} \sqrt{3}/2 \\\\\theta = 60^0

General solution for sin\theta is \theta = nπ + (-1)ⁿ ∝, where n ∈ Z.

If n is an even number say 2m, then \theta = (2m)π + ∝ where ∝ = 60° = π/3

Hence, the general solution to the equation will be \theta = 2mπ + π/3 for m ∈ Z.

8 0
3 years ago
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