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kirill115 [55]
3 years ago
8

Match the function with the graph. Please help it is TIMED.

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
D cause +2 means shift left and +3 means shift up
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The solution of equation 3n - 7 = 3 - 2n is????? I need this ans fast plsss
adoni [48]

Answer:

n=2

Step-by-step explanation:

3n-7=3-2n

5n=10 (add 2n on both sides and also add 7 on both sides of the equal sign)

n=2

DUBS

6 0
2 years ago
Read 2 more answers
Round 1.0649 to the nearest thousandth
ira [324]
1.0649 to the nearest thousandths is 1.065

You could get this by finding where the thousandths place is, which is the third number.
Now, look at the number to the right. 
If it's 5 or higher, round up. 
If it's 4 or lower, round down.

Since it is 9, we round up.
The 4 turns into a 5.

So, 1.065

Hope I helped!
6 0
3 years ago
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The table below shows the number of Japanese yen that could be exchanged for U.S. dollars on the day
olga55 [171]

Answer:

The Answer is B.

Step-by-step explanation:

7 0
3 years ago
Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
LUCKY_DIMON [66]
Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2
8 0
3 years ago
If you were to add 5 to my number and then divide by 4, you would get 7
Norma-Jean [14]
Let's make an equation. T will be the number.
(T+5)/4=7
Let's multiply both sides by 4 to get T by itself.
T+5=28
Subtract 5 from both sides.
T=23
Your number is 23.
3 0
2 years ago
Read 2 more answers
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