When we use arcsine, we are finding the angle while giving the trigonometric ratio.
Arcsin(u) = theta can be rewritten as:
sin(theta) = u
Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.
We can use Pythagorean Theorem to find the adjacent (x value).
1^2 - u^2 = x^2
x = sqrt(1-u^2)
Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).
Cosine is adjacent over hypotenuse.
So our answer is sqrt(1-u^2)/1
Or just sqrt(1-u^2)
<span>(Y-3)^2 = 4y -12 <=> Y^2 - 6Y + 9 = 4y - 12 <=> 4y = Y^2 - 6Y + 21 <=> y = (Y^2 - 6Y + 21)/4. Solving the equation for y means that we have to express y relative to the other quantities in the equation.</span>
Hey how are you doing today?
Answer:
1 5/12
Step-by-step explanation:
12 1/3 - 10 11/12
We need to get a common denominator of 12
12 1/3 * 4/4 - 10 11/12
12 4/12 - 10 11/12
We need to borrow from the 12 (the whole number) because the 2nd fraction is bigger than the first
12 becomes 11 and the 1 becomes 12/12
11+ (12/12 + 4/12) - 10 11/12
11 16/12 - 10 11/12
Subtract the whole numbers
11-10 =1
Subtract the fractions
16/12 - 11 /12 = 5 /12
We are left with 1 5/12
