Question

A horse race has 1313 entries and one person owns 44 of those horses. Assuming that there are no​ ties, what is the probability that those fourfour horses finish first comma second comma third comma and fourthfirst, second, third, and fourth ​(regardless of​ order)?

Answer 1

Answer: 0.0014

Step-by-step explanation:

Given : Number of entries in horse race = 13

Number of horses owned = 4

We assume that there are no​ ties .

Then , the probability that those four horses finish first, second ,third ,and fourth is given by :-

$\dfrac{4!}{^{13}P_4}=\dfrac{4!}{\dfrac{13!}{(13-4)!}}\\\\=\dfrac{4!\times9!}{13!}=.0013986013986\approx0.0014$

Hence, the required probability = 0.0014