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yarga [219]
3 years ago
11

A given flow field is defined by streamwise velocity component u = (8x) ft/s and cross-stream velocity component v = (8y) ft/s,

where x and y are in feet. Calculate the acceleration of a particle located at (x, y) = (2 ft, 1 ft) in this flow field, and state whether the flow is steady or unsteady. (Hint: Use the material derivative.)
Physics
1 answer:
stealth61 [152]3 years ago
3 0
Lol this easy 2+2 and then just add 4 that’s 8 add 3 more that’s 16 if you add 4

420vibesz
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A ball is dropped from a tower that is 206 m high, How long does it take to reach the ground?
Slav-nsk [51]

It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.

From the question given above, the following data were obtained:

Height (H) = 206 m

<h3>Time (t) =? </h3>

NOTE: Acceleration due to gravity (g) = 10 m/s²

The time taken for the ball to get to the ground can be obtained as follow:

H = ½gt²

206 = ½ × 10 × t²

206 = 5 × t²

Divide both side by 5

t^{2}  = \frac{206}{5}\\\\ t^{2} = 41.2

Take the square root of both side

t = \sqrt{41.2}

<h3>t = 6.42 s</h3>

Therefore, it will take 6.42 s for the ball to get to the ground.

Learn more: brainly.com/question/24903556

7 0
3 years ago
A closed cylinder with a 0.15-m radius ends is in a uniform electric field of 300 n/c, perpendicular to the ends. the total flux
bixtya [17]

The total flux through the cylinder is zero.


In fact, the electric flux through a surface (for a uniform electric field) is given by:

\Phi = E A \cos \theta

where

E is the intensity of the electric field

A is the surface

\theta is the angle between the direction of E and the perpendicular to the surface, whose direction is always outwards of the surface.


We can ignore the lateral surface of the cylinder, since the electric field is parallel to it, therefore the flux through the lateral surface of the cylinder is zero (because \theta=90^{\circ} and \cos \theta=0).


On the other two surfaces, the flux is equal and with opposite sign. In fact, on the first surface the flux will be

\Phi_1 = E \pi r^2

where r is the radius, and where we have taken \theta=0^{\circ} since the perpendicular to the surface is parallel to the direction of the electric field, so \cos \theta=1. On the second surface, however, the perpendicular to the surface is opposite to the electric field, so \theta=180^{\circ} and \cos \theta=-1, therefore the flux is

\Phi_2 = -E \pi r^2

And the net flux through the cylinder is

\Phi = \Phi_1 + \Phi_2 = E \pi r^2 - E \pi r^2=0

4 0
3 years ago
If a 50 kg student is standing on the edge of a cliff. Find the student’s gravitational potential energy if the cliff is 40 m hi
Oduvanchick [21]

you can find it using the equation: potential energy=mass*gravitational acceleration*height.


energy=50kg*9.8N/kg*40m=19600Nm=19600J or 19.6kJ


Sometimes they use 10 instead of 9.8 for the g constant. 


Rember to make me Brainliest!!!

3 0
4 years ago
Simplicity expression
Volgvan
They have expression<span>, modesty, sex appeal, </span><span>simplicity.</span>
7 0
4 years ago
Famous comparative and superlative form​
Helga [31]

Answer:

comparative----more famous, superlative----- most famous

3 0
3 years ago
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