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yarga [219]
3 years ago
11

A given flow field is defined by streamwise velocity component u = (8x) ft/s and cross-stream velocity component v = (8y) ft/s,

where x and y are in feet. Calculate the acceleration of a particle located at (x, y) = (2 ft, 1 ft) in this flow field, and state whether the flow is steady or unsteady. (Hint: Use the material derivative.)
Physics
1 answer:
stealth61 [152]3 years ago
3 0
Lol this easy 2+2 and then just add 4 that’s 8 add 3 more that’s 16 if you add 4

420vibesz
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Four model rockets are launched in a field. The mass of each rocket and the net force acting on it when it launches are given in
kondor19780726 [428]

Answer:

Rocket 2 has highest acceleration.

Explanation:

Net force,

F = mass (m) × acceleration (a)

We have,

m₁ = 4.25 kg and F = 120 N

a_1=\dfrac{F_1}{m_1}\\\\a_1=\dfrac{120}{4.25}\\\\a_1=28.23\ m/s^2

m₂ = 3.25 kg, F₂ = 120 N

a_2=\dfrac{F_2}{m_2}\\\\a_2=\dfrac{120}{3.25}\\\\a_2=36.92\ m/s^2

m₃ = 5.5 kg, F₃ = 120 N

a_3=\dfrac{F_3}{m_3}\\\\a_3=\dfrac{120}{5.5}\\\\a_3=21.81\ m/s^2

m₄ = 4.5 kg, F₄ = 120 N

a_4=\dfrac{F_4}{m_4}\\\\a_4=\dfrac{120}{4.5}\\\\a_4=26.66\ m/s^2

Hence, it can be seen that the highest acceleration is of rocket 2.

7 0
3 years ago
Starting from rest, a 75.0-kg snowboarder slides straight down a 115-m slope in 6.6 s. If the slope is a 35°
Likurg_2 [28]

The acceleration of the snowboarder is 5.6 m/s^2 down along the incline

Explanation:

To find the acceleration of the snowboard, we have to analyze the forces acting along the direction parallel to the incline.

There is only one force acting in this direction, and it is the component of the weight parallel to the incline, given by

mg sin \theta

where

m = 75.0 kg is the mass of the man

g=9.8 m/s^2 is the acceleration of gravity

\theta=35^{\circ} is the angle of the incline

Substituting, we find that the net force along the incline is:

F=(75.0)(9.8)(sin 35^{\circ})=421.6 N

According to Newton's second law, the net force on the snowboard is equal to the product between his mass and his acceleration:

F=ma

where a is the acceleration. Therefore, solving for a, we find

a=\frac{F}{m}=\frac{421.6}{75}=5.6 m/s^2

And the direction of this acceleration is down along the incline.

Learn more about acceleration and Newton's second law:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

8 0
3 years ago
During an experiment a student records the net horizontal force exerted on an object moving in a straight line along a horizonta
xeze [42]

Answer:c 40kg

Explanation:

4 0
3 years ago
Gravitational potential energy is always calculated with
ss7ja [257]

Answer:

kinetic energy as it involves dispersal of energy

7 0
3 years ago
Suppose we want a satellite to revolve around the earth 5 times a day. What should be the radius of its orbit? (The mass of the
Lyrx [107]

To solve this exercise we must apply the concepts related to the balance of forces.

For this particular case the force caused on the satellite from the planet must be equivalent to the Centrifugal Force, that is

F_g = F_c

\frac{GMm}{r^2} = m\omega^2 r

Where,

G = Gravitational Universal Constant

M = Mass of earth

m = mass of satellite

r = Distance/Orbit

Using the concept of Period through the angular velocity we have,

\frac{GM}{\omega^2} = r^3

\frac{GMT^2}{4\pi^2} = r^3

Finally re-arrange the equation to find the orbit and replacing, we have,

r^3 = \frac{6.67*10^{-11}*5.97*10^{24}}{4\pi^2}(\frac{24*3000}{5})^2

r^3 = 3.011*10^{21}

r = 1.44*10^7m

Therefor the orbit would be 14400 kilometers

5 0
4 years ago
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