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Blizzard [7]
3 years ago
12

What are the contour lines on a contour map?

Physics
2 answers:
Natasha_Volkova [10]3 years ago
7 0
In cartography, a contour line<span> (often just called a "</span>contour<span>") joins points of equal elevation (height) above a given level, such as mean sea level. A </span>contour map<span> is a </span>map<span> illustrated with </span>contour lines<span>, for example a </span>topographic map<span>, which thus shows valleys and hills, and the steepness of slopes.-hope that helped:)</span>
dalvyx [7]3 years ago
5 0
Contour lines are lines that signifies the elevation on a mountain or hill
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Whats A Controlled Experiment? Whats A Controlled Experiment? Like what the definition is please!
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A controlled experiment is when scientests go throw thests to make an experiment

3 0
3 years ago
You set out to design a car that uses the energy stored in a flywheel consisting of a uniform 101-kg cylinder of radius r that h
Ket [755]
Ok, assuming "mj" in the question is Megajoules MJ) you need a total amount of rotational kinetic energy in the fly wheel at the beginning of the trip that equals
(2.4e6 J/km)x(300 km)=7.2e8 J
The expression for rotational kinetic energy is

E = (1/2)Iω²  

where I is the moment of inertia of the fly wheel and ω is the angular velocity.  
So this comes down to finding the value of I that gives the required energy.  We know the mass is 101kg.  The formula for a solid cylinder's moment of inertia is

 I = (1/2)mR²

We want (1/2)Iω² = 7.2e8 J and we know ω is limited to 470 revs/sec.  However, ω must be in radians per second so multiply it by 2π to get 
ω = 2953.1 rad/s
Now let's use this to solve the energy equation, E = (1/2)Iω²,  for I:
I = 2(7.2e8 J)/(2953.1 rad/s)² = 165.12 kg·m²

Now find the radius R,

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√(2·165/101) = 1.807m

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8 0
3 years ago
A 975-kg elevator accelerates upward at 0.754 m/s2, pulled by a cable of negligible mass. Find the tension force in the cable.
Zina [86]

To solve this problem we will apply the concepts of equilibrium and Newton's second law.

According to the description given, it is under constant ascending acceleration, and the balance of the forces corresponding to the tension of the rope and the weight of the elevator must be equal to said acceleration. So

\sum F = ma

T-mg = ma

Here,

T = Tension

m = Mass

g = Gravitational Acceleration

a = Acceleration (upward)

Rearranging to find T,

T = m(g+a)

T = (975)(9.8+0.754)

T= 10290.15N

Therefore the tension force in the cable is 10290.15N

7 0
4 years ago
A car speeds up from 12.0 m/s to 16.0 m/s in 8.0 s. the acceleration of the car is?
maria [59]

Vi=12m/s Vf=16m/s t=8s a=? a=Vf-Vi/t=16-12/8=4/8=1/2 a=0.5m/s^2

6 0
3 years ago
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Xelga [282]

Answer:

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Explanation:

im big brain so i know lol

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