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dusya [7]
3 years ago
8

Chuck wants to know how many electrons in an atom are not paired up. Which model would be best for Chuck to write

Chemistry
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer:

D. an orbital notation of the atom

Explanation:

i took the test

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. Given the following pOH's, calculate the pH for the solution:
ryzh [129]

Answer:

a) pH = 9.82     b) pH = 1.65

a) pOH = 7.8     b) pOH = 4.45

Explanation:

pOH + pH = 14 for all of these solutions.

3 0
3 years ago
The pKb value for aqueous ammonia at 25
Alex17521 [72]

The value of pka for NH_3 in an aqueous solution is 9.2.

<h3>What is Kb?</h3>

Kb denotes the base dissociation constant.

pKa + pKb =14  at 25 degree celcius.

pKa + 4.8 =14

pKa = 9.2

pKb is the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.

It is used to determine the strength of a base or alkaline solution.

The value of pka for NH_3 in an aqueous solution is 9.2.

Learn more about pka here:

brainly.com/question/14124805

#SPJ1

8 0
1 year ago
What is the equilibrium constant expression for the given system?
artcher [175]
<h3>Answer:</h3>

\displaystyle K_{eq} = \frac{[H_2]^2[O_2]}{[H_2O]^2}

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • States of matter

<u>Kinetics</u>

  • Rate Laws

<u>Equilibrium</u>

  • Equilibrium Reactions RxN ⇄
  • Equilibrium Constants
  • Equilibrium Expression: \displaystyle K = \frac{[Producst]^{coefficients}}{[Reactants]^{coefficients}}
<h3>Explanation:</h3>

*Note: Only gases and liquids affect equilibrium

<u>Step 1: Define</u>

[RxN - Balanced] 2H₂O (g) ⇄ 2H₂ (g) + O₂ (g)

<u>Step 2: Identify</u>

[Reactant] H₂O

  • Coefficient of 2

[Product] H₂

  • Coefficient of 2

[Product] O₂

  • Coefficient of 1

<u>Step 3: Write K Expression</u>

  1. Substitute:                                                                                                       \displaystyle K_{eq} = \frac{[H_2]^2[O_2]}{[H_2O]^2}
5 0
2 years ago
Answer ASAP plzzz ! Will give Brainliest !
vesna_86 [32]

Answer:

27 mL

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

8 0
3 years ago
2A + N2 -&gt; 2AIN How many moles of aluminum nitride form when 5.00 g of aluminum reacts with excess nitrogen? K 0.0925 mol 0 0
Dafna1 [17]

Answer:

0.185 moles of AlN

Explanation:

The equation is:

2Al  +  N₂  →  2AlN

This reaction indicates that 2 mol of aluminum can react to 1 mol of nitrogen to produce 2 moles of aluminum nitride.

We convert the aluminum's mass to moles

5 g/ 26.98 g/mol = 0.185 moles.

2 moles of Al are needed to produce 2 moles of AlN

so, ratio is 1:1

In conclussion we say:

0.185 moles of Al, must produce 0.185 moles of AlN

5 0
3 years ago
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