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3 years ago

A patio has an area of 50. the width is 3/4 of the length. what is the length?

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

5 0

Answer:

37.5

Step-by-step explanation:

12.5x3=37.5

I hope i helped

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Miguel saved $355 in 5 weeks. He saved equal amounts of money each week. How much money would he save in 15.5 weeks ?

Andrei [34K]

Answer:

Step-by-step explanation:

$355:5

$355 divided by 5=$71

5 divided by 5=1

$71 per week

$71x15.5=$1,100.50

$1,100.50 in 15.5 weeks

7 0

3 years ago

Perry connects a blue garden hose and a green garden hose to make one long hose. The blue hose is 10.5 feet. The green hose is 1

swat32

Answer:

22.25 ft long

if you add 10.5 with 11.75 you'll get 22.25

7 0

3 years ago

sThe number of users on a social networking site was 45 thousand in February when theyofficially went public, and grew to 60 tho

svetoff [14.1K]

Given:

No of users in February is 45,000 and in october its 60,000.

$P=45000(\frac{4}{3})^{(\frac{3}{2})^t}$

t=2

$P=45000(\frac{4}{3})^3$ $P=45000(\frac{64}{27})$ $P=5000(\frac{64}{3})$ $P=106666.6667$

Therefore, approximate no of users after 2 years is 106667.

6 0

2 years ago

Unsure how to do this calculus, the book isn't explaining it well. Thanks

krok68 [10]

One way to capture the domain of integration is with the set

$D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}$

Then we can write the double integral as the iterated integral

$\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx$

Compute the integral with respect to $y$ .

$\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)$

Compute the remaining integral.

$\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}$

We could also swap the order of integration variables by writing

$D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}$

and

$\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy$

and this would have led to the same result.

$\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)$

$\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)$

7 0

1 year ago

PLEASE HELP!!! ILL GIVE BRANLIEST *EXTRA POINTS* dont skip :((

Dmitrij [34]

Answer:

2.333333333

Step-by-step explanation:

divide 3 into 7 and it's is repeating

5 0

3 years ago

Read 2 more answers