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vaieri [72.5K]
4 years ago
12

Which trinomials are perfect square trinomials?

Mathematics
1 answer:
pav-90 [236]4 years ago
4 0
A and D you are welcome
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Explain: how would you model 5 x 2/3
ELEN [110]
Well as you can see 5 x 2/3= 3 1/3 there is 7 steps to figure it out

1. set up the problem
5 x 2/3

2. put a 1 on 5 to make it a fraction
5/1 x 2/3

3. multiply and divide
(5 x 2) / (1/3)

4. find out the answer
10/3

5. turn the answer into a mixed fraction
10 divided by 3= 3.1 3 stays the same you don't need to say 1

6. it equals
3 1/3

7. so the answer is
3 1/3

8 0
3 years ago
Read 2 more answers
I have to write this on graph paper please help this is due tomorrow
eduard

Answer:

the answer is in the link

Step-by-step explanation:

4 0
2 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
DerKrebs [107]

Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

6 0
3 years ago
HELP PLEASE Enter the equation of the circle with the given center and radius.
masha68 [24]

Answer:

(x + 2)² + (y + 9)² = 49

Step-by-step explanation:

Equation:

(x - h)² + (y - k)² = r²

(x - -2)² + (y - -9)² = 7²

(x + 2)² + (y + 9)² = 49

5 0
3 years ago
HELP<br> Please<br> Please<br> im failing
Reptile [31]

Answer:

6.9

7.-5

8.-10

Step-by-step explanation:

3 0
3 years ago
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