4 1/6 = 4 7/42
2 4/7 = 2 24/42
2 24/42 + 4 7/42 = 6 31/42
6 31/42 = 283/42
<h2>
Answer with explanation:</h2>
As per given , we have
Sample size : n= 5
Degree pf freedom = : df= 5-1=4
Significance level for 90% confidence = 
Using t-value table , t-critical value for 90% confidence:
Margin of error of 
: 
Interpretation : The repair cost will be within $12.39 of the real population mean value 90% of the time.
To find the mean you add all the numbers then divide the sum by how many numbers there are :
1)Ford School
21+19+20=60
there are 3 numbers in the equation so you divide 60 by 3 :
60÷3=20
the mean for Ford School is 20
2)Carter School
41+36+37=114
there are 3 numbers in the equation so you divide 114 by 3 :
114÷3=38
the mean for Carter School is 38
hope this helps
The reflected points are (4, -1) and (-2, 6).
Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1) eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
