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yulyashka [42]
4 years ago
5

From the 1,2,3,4,5 which values make the inequality n+1 > 4 true?

Mathematics
2 answers:
shusha [124]4 years ago
8 0

Answers: {4, 5}

========================================================

Explanation:

We have some number n and we're adding 1 to it to get n+1.

This n+1 is larger than 4. We want to find which values make n+1 > 4 true.

To find out, undo the operation "add 1" by subtracting 1 from both sides

n+1 > 4

n+1-1 > 4-1

n+0 > 3

n > 3

Anything larger than 3 will work. So that means {4,5} is the solution set from the original list of values.

For instance, if we tried n = 5, then

n+1 > 4

5+1 > 4 ... replace n with 5

6 > 4 ... true statement

But if we tried n = 1, then,

n+1 > 4

1+1 > 4

2 > 4 ... false; this shows n = 1 isn't in the solution set.

ELEN [110]4 years ago
4 0

Answer:

yes it is

Step-by-step explanation:

hope I helped;)

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3 years ago
Hank has 50 peso, 200 peso and 500 peso bills in his wallet. He has five less 200 bills as 50 bills, and half as many 500 bills
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For an amount of 6250 Peso, Hank have the quantities of the following denominations: 2503 bills of 50 peso, 2498 bills of 200 peso and 1249 bills of 500 peso.

<h3>How to apply systems of linear equations in real life equations</h3>

In this question we must translate the statement of the problem into mathematical expressions and then we must solve the resulting system. We need three equations that describe the quantities of 50 peso, 200 peso and 500 peso bills:

<em>y = x - 5</em>     (1)

<em>0.5 · y =</em> <em>z</em>    (2)

<em>x + y + z = 6250</em>     (3)

The solution of the system of <em>linear</em> equations is described below:

<em>x =</em> 2503, <em>y =</em> 2498, <em>z =</em> 1249

For an amount of 6250 Peso, Hank have the quantities of the following denominations: 2503 bills of 50 peso, 2498 bills of 200 peso and 1249 bills of 500 peso. \blacksquare

To learn more on systems of linear equations, we kindly invite to check this verified question: brainly.com/question/20379472

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<u>f(x)=x²-2x-2</u>

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