Answer:
Step-by-step explanation:
integral(x/(1+x^2)^2)dx
=(1/2)integral(2x/(1+x^2)^2)dx
=(1/2)[-1/(1+x^2)] +c
Let 4 + 3x = u
then 3dx = du
or, <span>1/3∫<span>u√</span>du
</span>
= <span>1/3<span>u^<span>3/2</span></span>/(3/2)
</span>
= <span>2/9∗(4+3x<span>)^<span>3/2
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Answer:
Start at -150, then add 3(-5), then add 122.2. -150 + 3(-5) + 122.2 = -45.3.
The answer to your question is the letter G.
