Represent as
w=wally
a=ashan
so wally has 2 more marbles than ashan
w=2+a
together they have 88
w+a=88
since w=2+a, subsitute (2+a) for w in the w+a=88 equation
2+a+a=88
add like terms
2+2a=88
subtract 2 from both sides
2a=86
divide by 2
a=43
ashan has 43 marbles
Answer:
a : b = 4 : 3
Step-by-step explanation:
(mark as brainlist answer)
According to the given condition is the question :
Two numbers a and b are such that the sum of 5% of a and 4% of b is two-third of the sum of 6% of a and 8% of b
⇒ (5% of a) + (4% of b) = (2/3) × [(6% of a) + (8% of b)
⇒ 0.05a + 0.04b = 2/3 × (0.06a + 0.08b)
⇒ 0.15a + 0.12b = 0.12a + 0.16b
⇒ 0.03a = 0.04b
⇒ a/b = 4/3
⇒ a : b = 4 : 3
