I think the missing word you're looking for here is 'unit'. The examples such as kilogram and gallons are all units of measurement. These are standard amounts used for mass, volume, and length. It is especially important to be consistent with this units especially when doing dimensional analysis.
Answer:
8 kg*m/s and 2m/s
Explanation:
momentum is mass times velocity. since the velocity changes by 2 m/s. you just take the difference from final velocity to beginning velocity.
4kg*12m/s = 48 kg*m/s
4kg*10m/s = 40 kg*m/s
48kg*m/s - 40 kg*m/s = 8kg*m/s
#1
As we know that
now plug in all data into this
now from the formula of strain
#2
As we know that
pressure * area = Force
here we know that
now force is given as
#3
As we know that density of water will vary with the height as given below
here we know that
now density is given as
#4
as we know that pressure changes with depth as per following equation
here we know that
now we will have
here we will have
so it is 20.1 m below the surface
#5
Here net buoyancy force due to water and oil will balance the weight of the block
so here we will have
so it is 3.48 cm below the interface
Answer:
Explanation:
Given
initial speed(u)=5 m/s
Final speed(v)=4 m/s
Distance traveled=3 m
using equation of motion
after this its final velocity will be zero
s=5.33 m
Total distance=3+5.33=8.33 m
Thus he will not be able to win the game
A)<span>
dQ = ρ(r) * A * dr = ρ0(1 - r/R) (4πr²)dr = 4π * ρ0(r² -
r³/R) dr
which when integrated from 0 to r is
total charge = 4π * ρ0 (r³/3 + r^4/(4R))
and when r = R our total charge is
total charge = 4π*ρ0(R³/3 + R³/4) = 4π*ρ0*R³/12 = π*ρ0*R³ / 3
and after substituting ρ0 = 3Q / πR³ we have
total charge = Q ◄
B) E = kQ/d²
since the distribution is symmetric spherically
C) dE = k*dq/r² = k*4π*ρ0(r² - r³/R)dr / r² = k*4π*ρ0(1 -
r/R)dr
so
E(r) = k*4π*ρ0*(r - r²/(2R)) from zero to r is
and after substituting for ρ0 is
E(r) = k*4π*3Q(r - r²/(2R)) / πR³ = 12kQ(r/R³ - r²/(2R^4))
which could be expressed other ways.
D) dE/dr = 0 = 12kQ(1/R³ - r/R^4) means that
r = R for a min/max (and we know it's a max since r = 0 is a
min).
<span>E) E = 12kQ(R/R³ - R²/(2R^4)) = 12kQ / 2R² = 6kQ / R² </span></span>