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3 years ago

Open Meet and enter this code: jnw-xodp-yij

Physics

2 answers:

nikdorinn [45]3 years ago

8 0

Answer:

nrjfnvsncjanxsafkemfksevnjenf thx for the points i guess

Explanation:

Arada [10]3 years ago

5 0

Answer:

Is this for zoommmmmmmmmm?

Explanation:

It had to be 20 letters I had to do something

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C, N, Ne, Ar which contains a metal, nonmetal, noble gas , metalloid

postnew [5]

Answer:

c,carbono nonmetal

n, nitrogen nonmetal

ne, neón noble gas

ar,argon noble gas

4 0

3 years ago

Assume that a clay model of a lion has a mass of 0.225 kg and travels on the ice at a speed of 0.85 m/s. It hits another clay mo

Charra [1.4K]

Answer:

Final velocity will be equal to 0.321 m/sec

Explanation:

We have given mass of clay model of lion $m_1=0.225kg$

Its speed is 0.85 m/sec, so $v_1=0.85m/sec$

Mass of another clay model $m_2=0.37kg$

It is given that second clay is motionless

So its velocity $v_2=0m/sec$

Now according to conservation of momentum

Momentum before collision will be equal to momentum after collision

So $m_1v_!+m_2v_2=(m_1+m_2)v$ , here v is velocity after collision

So $0.225\times 0.85+0.37\times 0+(0.225+0.37)v$

$0.595v=0.191$

v = 0.321 m/sec

So final velocity will be equal to 0.321 m/sec

5 0

3 years ago

You are driving at the speed of 29.5 m/s

svp [43]

Answer:

honestly not sure what to do good luck though

3 0

2 years ago

What is the frequency of a wave whose wavelength is 0.7m and whose velocity is 120m/s?

ANEK [815]

Answer:

f=171.43Hz

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

The frequency formula is: f=v÷λ, where <em>v</em> is the velocity and <em>λ</em> is the wavelength.

Then replacing with the data of the problem,

f= $\frac{120\frac{m}{s} }{0.7m}$

f=171.43 $\frac{1}{s}$

f=171.43 Hz (because $\frac{1}{s} = Hz$ , 1 hertz equals 1 wave passing a fixed point in 1 second).

5 0

4 years ago

Which of the following changes will increase the period of an oscillating spring mass system?

atroni [7]

Answer:

a. an increase in the mass on the spring.

Explanation:

An increase in the mass on the spring will increase the period of an oscillating spring mass system.

Mathematically, the period of an oscillating spring mass system is given by the formula;

T = 2π √(m/k)

Where;

T is the period.

m is the mass of the spring.

k is the spring constant.

Hence, the mass of a spring is directly proportional to the period of oscillation of the spring.

This ultimately implies that, as the mass of the spring increases, the period of oscillation will increase. Similarly, the period of oscillation will decrease with an increase in the spring constant i.e there exist an inverse relationship between the period and spring constant.

8 0

3 years ago

Open Meet and enter this code: jnw-xodp-yij​

Open Meet and enter this code: jnw-xodp-yij