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denpristay [2]
3 years ago
14

FH and IK aré parallel lines

Mathematics
1 answer:
Damm [24]3 years ago
6 0

Answer:

cAN YOU SHOW ME THE DIAGRAM FOR THE QUESTIOn?

Step-by-step explanation:

You might be interested in
The rectangle below has an area of 70y^8+30y^6.The width of the rectangle is equal to the greatest common monomial factor of 70y
swat32

Answer:

Width 10y^6 units

Length 7y^2+3 units

Step-by-step explanation:

The rectangle has an area of 70y^8+30y^6.

The width of the rectangle is equal to the greatest common monomial factor of 70y^8 and 30y^6. Find this monomial factor:

70y^8=2\cdot 5\cdot 7\cdot y^8\\ \\30y^6=2\cdot 3\cdot 5\cdot y^6\\ \\GCF(70y^8,30y^6)=2\cdot 5\cdot y^6=10y^6

Hence, the width of the rectangle is 10y^6 units.

The area of the rectangle can be rewritten as

10y^6(7y^2+3).

The area of the rectangle is the product of its width by its length, then the length of the rectangle is 7y^2+3 units.

8 0
4 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
brilliants [131]
First set up a proportion because they are similar triangles:
9/3x-20 = (72+9)/(56+3x-20)
9/3x-20 = 81/3x+36
9(3x+36) = 81(3x-20)
27x+324 = 243x-1620
1944 = 216x
x = 9
4 0
3 years ago
Read 2 more answers
If the speed limit on a interstate is 45 and someone is going 85 how much more are they going than the speed limit?
-Dominant- [34]

Answer:

40 miles over the speed limit

Step-by-step explanation:

You want the difference between the two numbers so you subtract 45 from 85 which gives you 40

3 0
3 years ago
Read 2 more answers
A home improvement contractor is painting the walls and ceiling of a rectangular room. The volume of the room is 1584 cubic feet
liq [111]

Answer:

The room dimensions that will minimize the cost of the paint are 12 ft x 12 ft x 11 ft.

Step-by-step explanation:

We can find first the volume equation using the formula of the volume of a box.

V= xyz

Thus we get the constraint function

1584 = xyz

Then since we are asked to minimize the cost, we can write the cost function which is the area of each one of the walls and ceiling multiplied by the painting cost.

C=0.11 xy+ 2(0.06)xz+2(0.06yz \\ C =0.11 xy+0.12xz+0.12yz

Lagrange Multipliers to find minimum cost.

We can continue finding the partial derivatives to build the system of equations required for Lagrange Multipliers method.

C_x=\lambda V_x \\ C_y = \lambda V_y \\ C_z = \lambda V_z

And the constraint function

xyz=1584

So we get

0.11y+0.12z=\lambda yz \\ 0.11x+0.12z=\lambda xz \\ 0.12x+0.12y=\lambda xy\\ xyz=1584

We can multiply each side of each equation by the dimension which is missing to get the full volume on the right side.

0.11xy+0.12xz=\lambda xyz \\ 0.11xy+0.12yz=\lambda xyz \\ 0.12xz+0.12yz=\lambda xyz

Then we can set each the equations equal to each other, so from the first one and the second equation we get

0.11xy+0.12xz= 0.11xy+0.12yz

We can subtract 0.11xy from both sides.

0.12xz=0.12yz

And we can divide both sides by 0.12z to get

x=y

We can repeat the process by setting the first and third equation equal to each other.

0.11xy+0.12xz= 0.12xz+0.12yz

We can subtract 0.12 xz from both sides

0.11xy=0.12yz

And we can solve by z

z= \cfrac{0.11x}{0.12}\\ z = \cfrac{11x}{12}

So if we replace that as well y = x on the constraint for the volume euqation we get

1584=x(x)\left(\cfrac{11}{12}x\right) \\ 1584=\cfrac{11}{12}x^3

We can then solve for x

x^3 = \cfrac{1584(12)}{11}

And taking the cube root

x = \sqrt[3]{\cfrac{1584(12)}{11}}

x = \sqrt[3]{1728}

x=12 ft

So then we can use the equations we have found for y and z in terms of x

y = x \\ y = 12 ft

And

z= \cfrac{11x}{12}\\z= \cfrac{11(12)}{12} \\ z=11ft

Then the dimensions of the room that will minimize the cost are 12ft x 12 ft x 11 ft. Since you have to enter using commas you can write 12, 12, 11, please check as well if you have to insert the units that are feet for each.

5 0
4 years ago
A production system has a total daily output of 400 units and a total labor of 350 hours, what kind of productivity measure can
fomenos

Answer:

1.14 products per hour of labor

Step-by-step explanation:

To calculate the daily productivity would be the amount of products per hour of labor.

That is: 400 products / 350 hours of labor, and that is approximately 1.14 products per hour of labor.

Which means that for every hour of labor, 1.14 products are produced in one day, which would be a factor of productivity.

4 0
3 years ago
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