3 years ago

Please explain this type of problem (1+2i)(1+3i)

Mathematics

1 answer:

zhuklara [117]3 years ago

7 0

Answer:

-5(1-I) is the answer

Step-by-step explanation:

(1+2i)(1+3i)

1(1+3i)+2i(1+3i)

1+3i+2i+6i^2

As i^2=-1

1+5i+6(-1)

1-6+5i

-5+5i

Taking -5 as common

-5(1-i)

I hope this will help you :)

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