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3 years ago

Please explain this type of problem (1+2i)(1+3i)

Mathematics

1 answer:

zhuklara [117]3 years ago

7 0

Answer:

-5(1-I) is the answer

Step-by-step explanation:

(1+2i)(1+3i)

1(1+3i)+2i(1+3i)

1+3i+2i+6i^2

As i^2=-1

1+5i+6(-1)

1-6+5i

-5+5i

Taking -5 as common

-5(1-i)

I hope this will help you :)

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Max built a rectangular Prism and a rectangular Pyramid using beach sand. The prism and the pyramid have the same base area and

vova2212 [387]

Answer:

Three times

Step-by-step explanation:

Given

Figures: Rectangular Prism and Rectangular Pyramid

Let the dimension of the prism be:

$l = length$

$w = width$

$h = height$

Amount of sand used is the volume (V1) and it is calculated using;

$V_1 = l * w * h$

$V_1 = lw h$

Since the pyramid has the same base area and height as the prism, the its dimension would be:

$l = length$

$w = width$

$h = height$

Amount of sand used is the volume (V2) and it is calculated using;

$V_2 = \frac{1}{3}*(lwh)$

So, we have:

$V_1 = lw h$

$V_2 = \frac{1}{3}*(lwh)$

Substitute lwh for V1 in the second equation

$V_2 = \frac{1}{3}V_1$

Multiply both sides by 3

$3 * V_2 = \frac{1}{3}V_1 * 3$

$3 * V_2 = V_1$

Reorder

$V_1 = 3 * V_2$

$V_1 = 3 V_2$

<em>Hence, the amount of sand used in building the prism is three times the amount of sand used in building the pyramid</em>

3 0

3 years ago

What is y=-4/3x +6. y=2

Mekhanik [1.2K]

The given equation is:
[/tex]y=-\frac{4}{3}x+6 [/tex] and we need to evaluate this for y=2.
So, first step is to plug in 2 for y in the above equation. Therefore,

$2=-\frac{4}{3} x+6$
$2*3=-\frac{4}{3} x*3+6*3$ Multiply each sides by common denominator 3
$6=-4x+18$
6-18= -4x Subtract 18 from each sides.
-12=-4x
$-\frac{12}{-4} =-\frac{4x}{-4}$
So, x=3

5 0

2 years ago

What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti

Marat540 [252]

Answer:

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

Step-by-step explanation:

Given

$x^2 - 5x - 7 = 0$

Required

Solve for x using:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

First, we need to identify a, b and c

The general form of a quadratic equation is:

$ax^2 + bx + c = 0$

So, by comparison with $x^2 - 5x - 7 = 0$

$a = 1$ $b = -5$ $c = -7$

Substitute these values of a, b and c in

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}$

$x = \frac{5 \± \sqrt{25 +28}}{2}$

$x = \frac{5 \± \sqrt{53}}{2}$

Split the expression to two

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

To solve further in decimal form, we have

$x = \frac{5 + 7.28}{2}$ or $x = \frac{5 - 7.28}{2}$

$x = \frac{12.28}{2}$ or $x = \frac{-2.28}{2}$

$x = 6.14$ or $x = -1.14$

4 0

3 years ago

Two unidentified flying discs are detected by a receiver. The angle of elevation from the receiver to each disc is 39.48 degree.

lys-0071 [83]

Answer:

The answer is "298.83 m"

Step-by-step explanation:

Its gap from its transmitter from each disc comprises of 2 triangles. Its horizontal segment via disc to vertical, and longitudinal segment. Disk height, h, is parallel to a horizontal disc Wink including its line across recipient to disc or horizontal 39. 48^{\circ}

$\to 39. 48^{\circ} = \frac{h_1}{826 \ m}\\\\ \to 826\ m (\ sin 39. 48^{\circ} ) = h_1\\\\ \to 525.18 = h_1\\\\$

if:

$\to \sin 39. 48^{\circ} = \frac{h_2}{1.296 \ km}\\\\ \to \sin 39. 48^{\circ} (1296 \ m) = h_2\\\\ \to 824.01 = h_2\\\\\to h_2 - h_1 = 824.01 - 525.18\\\\$

$= 298.83 \ m$

4 0

3 years ago

What is the distance between...

ss7ja [257]

what do you mean ¨ what is the distance between¨ what is the rest of the question?

8 0

2 years ago