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Elden [556K]
3 years ago
9

Please explain this type of problem (1+2i)(1+3i)

Mathematics
1 answer:
zhuklara [117]3 years ago
7 0

Answer:

-5(1-I) is the answer

Step-by-step explanation:

(1+2i)(1+3i)

1(1+3i)+2i(1+3i)

1+3i+2i+6i^2

As i^2=-1

1+5i+6(-1)

1-6+5i

-5+5i

Taking -5 as common

-5(1-i)

I hope this will help you :)

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What is a simple formula to solve a math sequence? Or a couple formulas if possible? Thanks!
-Dominant- [34]
2 normal types of sequences:

1. arythmetic sequences: each term is the same distance to the next term, example, 2,4,6,8, distance is 2

2. geometric sequences: the ratio of consecutive terms is the same, example: 2,4,8,16, ratio is 4:2=2:1, 2/1=2


the nth term is denoted by a_{n}
the first term is represented by a_{1}

for arythmetic sequences, the nth tem is
a_{n}=a_{1}(n-1)d where d=distance between each term

for geometric sequences the nth term is
[tex] a_{n}=a_{1}r^{n-1} where r=ratio betwen consecutive terms

7 0
3 years ago
Find the average rate of change of f(x)=-x2+2x+2 from x=2 to x=6
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6 0
2 years ago
What value of x makes the equation 3(x - 6) - 8x = -2 + 5(2x + 1) true ?
Romashka-Z-Leto [24]

Answer:

x = -3

Step-by-step explanation:

3(x - 6)= -2 + 5(2x + 1)

= 3x - 18 = -2 + 10x + 5

= -18 = -2 + 7x + 5

= -18 = 7x + 3

= -21 = 7x

= -3 = x

= x = -3

5 0
3 years ago
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side
lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

       =cot x (sec²x)²

       =cot x (1+tan²x)²     [ ∵ sec²x=1+tan²x]

       =  cot x(1+ 2 tan²x +tan⁴x)

       =cot x+ 2 cot x tan²x+cot x tan⁴x

        =cot x +2 tan x + tan³x        [ ∵cot x tan x =\frac{ \textrm{tan x }}{\textrm{tan x}} =1]

       =R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

 L.H.S =(sin x)(tan x cos x - cot x cos x)

          = sin x tan x cos x - sin x cot x cos x

           =\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}

           = sin²x -cos²x

           =1-cos²x-cos²x

           =1-2 cos²x

           =R.H.S

         

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

         =1+\frac{{sin^2x}}{cos^2x}                       [\textrm{sec x}=\frac{1}{\textrm{cos x}}]

         =1+tan²x                        [\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]

         =sec²x

        =R.H.S

4.

\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}

L.H.S=\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}

       =\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}

      =\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}

     =\frac{\textrm{2sin x}}{sin^2 x}

      = 2 csc x

    = R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

        = sec²x-tan²x

        =\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}

        =\frac{1- sin^2x}{cos^2x}

        =\frac{cos^2x}{cos^2x}

        =1

     

       

8 0
3 years ago
Which symbol creates a true sentence when x equals 2? 6 • 8 – 2x _____ 6(5 + x) < > = ?
34kurt
48-4=44,in the left
6×7=42,in the right
44>42,so > is the answer
5 0
3 years ago
Read 2 more answers
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