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Elden [556K]
3 years ago
9

Please explain this type of problem (1+2i)(1+3i)

Mathematics
1 answer:
zhuklara [117]3 years ago
7 0

Answer:

-5(1-I) is the answer

Step-by-step explanation:

(1+2i)(1+3i)

1(1+3i)+2i(1+3i)

1+3i+2i+6i^2

As i^2=-1

1+5i+6(-1)

1-6+5i

-5+5i

Taking -5 as common

-5(1-i)

I hope this will help you :)

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Answer:

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Step-by-step explanation:

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3 years ago
Expand and simplify 2(a + 3) + 3(2a - 1)
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2(a+3) + 3(2a-1)
First, let's use the distributive property to expand 2(a+3):
2(a+3) = 2*a + 2*3 = 2a + 6
Let's use the distributive property now to expand 3(2a-1):
3(2a - 1) = 3*2a - 3*1 = 6a - 3

So 2(a+3) + 3(2a-1) = 2a + 6 + 6a - 3
Now you calculate variables between each others, and numbers between each others:
2a + 6 + 6a - 3 = 2a + 6a + 6 - 3 = 8a + 3

So the simplified form of 2(a+3) + 3(2a-1) is 8a + 3.

Hope this Helps! :)
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4 years ago
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MA_775_DIABLO [31]

Answer:

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Step-by-step explanation:

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3 years ago
How are functions related to solving linear equations
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