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Lubov Fominskaja [6]
3 years ago
14

The ideal gas law (PV=nRT) describes the relationship between pressure P, volume V, temperature T, and molar amount n. When n an

d V are fixed, the equation can be rearranged to take the following form where k is a constant:
Boyle's law PV=nRT=kn and T; Charles's law VT=nRP=kn and P; Avogadro's law Vn=RTP=kT and P.
A certain amount of chlorine gas was placed inside a cylinder with a movable piston at one end. The initial volume was 3.00 L and the initial pressure of chlorine was 1.80 atm. The piston was pushed down to change the volume to 1.00 L.
Calculate the final pressure of the gas if the temperature and number of moles of chlorine remain constant. Express your answer with the appropriate units.
Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

Answer:

New pressure is 5.40 atm

Explanation:

When T° and moles remain constant, we should use these relation to determine pressure, or also volume

P₁ . V₁ = P₂ . V₂

1.80 atm . 3L = P₂ . 1L

(1.80 atm . 3L ) / 1L = P₂

5.40 atm = P₂

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What volume will 1.27 moles of helium gas occupy at 80.00 °C and 1.00 atm?
White raven [17]

Answer:

36.8 L

Explanation:

We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 80 °C

T(K) = 80 + 273

T(K) = 353 K

Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:

Number of mole (n) = 1.27 moles

Temperature (T) = 353 K

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 1.27 × 0.0821 × 353

V = 36.8 L

Thus, the volume occupied by the helium gas is 36.8 L

5 0
3 years ago
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Answer:

The answer is option 3.

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sleet_krkn [62]

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