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3 years ago

What volume will 1.27 moles of helium gas occupy at 80.00 °C and 1.00 atm?

Chemistry

1 answer:

White raven [17]3 years ago

5 0

Answer:

36.8 L

Explanation:

We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 80 °C

T(K) = 80 + 273

T(K) = 353 K

Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:

Number of mole (n) = 1.27 moles

Temperature (T) = 353 K

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 1.27 × 0.0821 × 353

V = 36.8 L

Thus, the volume occupied by the helium gas is 36.8 L

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A sailor on a trans-Pacific solo voyage notices one day that if he puts 735.mL of fresh water into a plastic cup weighing 25.0g,

Gennadij [26K]

Answer:

Amount of salt in 1 L seawater = 34 g

Explanation:

According to Archimedes' principle, mass of freshwater and cup = mass of equal volume of seawater

mass of freshwater = density * volume

1 cm³ = 1 mL

mass of freshwater = 0.999 g/cm³ * 735 cm³ = 734.265 g

mass of freshwater + cup = 734.265 + 25 = 759.265 g

Therefore, mass of equal volume of seawater = 759.265 g

Volume of seawater displaced = 735 mL = 0.735 L (assuming the cup volume is negligible)

1 liter = 1000 cm³ = 1000 mL;

Density of seawater = mass / volume

Density of seawater = 759.265 g / 0.735 L = 1033.01 g/L

Density of freshwater in g/L = 0.999 g/ (1/1000) L = 999 g/L

mass of 1 Liter seawater = 1033.01 g

mass of 1 Liter freshwater = 999 g

mass of salt dissolved in 1 L of seawater = 1033.01 g - 999 g = 34.01 g

Therefore, amount of salt in 1 L seawater = 34 g

4 0

3 years ago

Identify the double displacement reaction. 3Pb 2h 3PO 4 ⟶ 3H 2 Pb 3(PO 4) 2 2NO 2 ⟶ 2O 2 N 2 2NaBr Ca(OH) 2 ⟶ CaBr 2 2NaOH 2NH 3

IRISSAK [1]

Reaction 3 is the double displacement reaction.

Double displacement reaction occurs when the negatively and the positively charged ions of the compounds interchange their position when the new compound in the product is formed.

<h3>Which is a double displacement reaction?</h3>

In the first reaction, the element lead (Pb) is not an ion and no exchange of the cations or the anions occurs hence it is not a double displacement reaction.

In the second reaction, one compound is getting split into two new compounds and is a decomposition reaction.

In the third reaction, $\rm Br^{-}$ in $\rm 2NaBr$ and $\rm (OH)_{2}$ in $\rm Ca(OH)_{2}$ are anions and cations and exchanges their places to produce two new compounds $\rm CaBr_{2} + 2NaOH.$

In the fourth reaction, a single compound is generated as the result of the combination reaction and hence, it is not the double displacement reaction.

Therefore, $\rm 2NaBr + Ca(OH)_{2} \rightarrow CaBr_{2} + 2NaOH$ is the double displacement reaction.

Learn more about double displacement reaction here:

brainly.com/question/10091171

3 0

1 year ago

a student needs to use 0.575 moles of sodium chloride in an experiment. How many grams should he mass out?

Bad White [126]

The molecular weight of NaCl is 58.44 g/mol.

0.575 mol * 58.44 g/mol = 33.6 grams of NaCl

5 0

3 years ago

atroni [7]

Answer:

(1) atomic numbers

Explanation:

The observed regularities in the properties of the elements on the periodic table are periodic functions of their atomic numbers.

Atomic number is the number of protons in an atom.
The periodic law states that "the properties of elements are a periodic function of their atomic number".
Elements on the periodic table are arranged based on the atomic numbers they contain.
The number of positively charged particles in an atom is the atomic number.

6 0

2 years ago

The disaccharide lactose can be decomposed into its constituent sugars galactose and glucose. This decomposition can be accompli

n200080 [17]

Answer:

Rate = 116m⁻¹s⁻¹[lactose][H]⁺

Explanation:

the formula for rate of reaction is given as

Rate = k[lactose]∧α[H]⁺∧β

we solve for the value of α and β

([lactose]₁/[lactose]₂)∧α

α = $\frac{ln\frac{0.00116}{0.00232} }{ln\frac{0.01}{0.02} }$

when we divide this equation

α = $\frac{ln0.5}{ln0.5}$

α = 1

we find β

R₁/R₂ = 0.01/0.02(0.001/0.001)∧β

0.00116/0.00232 = 0.5(1)∧β

β = 1

Rate = k[lactose]∧α[H]⁺∧β

we have to find the value for k

k = 0.00116/0.01(0.001)

k = 0.00116/0.00001

= 116m⁻¹s⁻¹

Rate = 116m⁻¹s⁻¹[lactose][H]⁺

3 0

2 years ago