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Kaylis [27]
3 years ago
5

What is the % Hydrogen in glucose

Chemistry
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

50%

Explanation:

Hydrogen makes up about 50% in glucose in atoms, in mass, 6.7 wise

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Determine how many moles of O2 are required to react completely with 4.6 mol of C4H10
kondaur [170]

Answer:

29.9 moles

2C²H¹⁰ needs 13 moles of O²

4.6 C⁴H¹⁰ needs X moles of O²

X= 13× 4.6 ÷ 2 = 59.8 ÷ 2 = 29.9 moles

3 0
3 years ago
1 which equation demonstrates the law of conservation of mass?
Mrac [35]
Every balanced chemical reaction demonstrates the law of conservation of mass where the reactants have the same number of atoms as the products. For example, the production of ammonia gas.
N2 (g) + 3H2 (g) -> 2NH3 (g) you can see that there are two nitrogen atoms and six hydrogen atoms on both sides of the equation.
5 0
3 years ago
What is distance<br>who knows pls ASAP​
notsponge [240]

Answer: an amount of space between two things or people.

Explanation: hope this helps? :)

6 0
3 years ago
can someone please help me write a lab report if yes i will give u the information please i need for tommorow
shusha [124]
I may be able to depending on what it is about. 

Can you give me the info?
3 0
3 years ago
_Al(s) + - 02(g) → _Al2O3 (s)<br> Balance equation
AfilCa [17]
<h2>Al (s) +   O₂ (g)----> Al₂O₃(s)</h2>

Explanation:

Chemical reaction

When two or more substances react and form some new substance it is called as chemical reaction .

For example :

Al (s) +   O₂ (g)----> Al₂O₃(s)

Chemical equation

It is the representation of chemical reaction in terms of symbols ,molecular formulas ,moles , states  etc .

As we know all chemical reaction obeys law of chemical combination therefore chemical reaction need to be balanced .  

Law of conservation of mass

Mass can neither be created nor be destroyed in a chemical reaction , it is always conserved .That is why reactions need to be balanced .

Let us balance

Al (s) +   O₂ (g)----> Al₂O₃(s)

After balancing , it becomes :

2Al (s) +   3/2O₂ (g)----> Al₂O₃(s)

6 0
3 years ago
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