All categories

3 years ago

If eggs cost $3 per dozen. how much would 8 eggs cost?

Mathematics

2 answers:

Anna11 [10]3 years ago

6 0

2 dollars. because when you divide 12 by 3 you get 4. so four eggs are one dollar. so then 8 eggs would be 2 dollars

weeeeeb [17]3 years ago

3 0

12 eggs = $3
8 eggs = (8÷12) × $3

hope this was helpful! :)

You might be interested in

Write an equation of the line that passes through (1,2) and is parallel to the line y = -5x +4

STatiana [176]

Answer:

y=-5x+7

Step-by-step explanation:

Prallel lines have the same slope

so the slope of the unknown line is -5

and passes through(1,2)

y-2=-5(x-1)

slope-intercept form:y=-5x+7

6 0

3 years ago

Carmen's golf score is 6 strokes less than Linda's. Their two scores total 156. What is each girls score?

DochEvi [55]

Answer:

Carmen's score is 75 strokes.

Linda's score is 81 strokes.

Step-by-step explanation:

Let the score of Linda be "x".

<em>It is given that Carmen's golf score is 6 strokes less than Linda's.</em>

Thus, Carmen's score is (x-6).

The total score of the girls is

= $x + (x-6) = 2x-6$

The total score is given to be 156.

Thus, the equation becomes,

$2x-6 = 156$

$2x= 162$

$x = 81$

<em>Thus Linda's score is 81 and Carmen's score is (156-81) 75.</em>

5 0

3 years ago

Find functions f and g such that h = g ∘ f. (note: the answer is not unique. enter your answers as a comma-separated list of fun

polet [3.4K]

It is given in the question that

$h(x) = (fog)(x) = x^2 -81$

And $x^2 -81$

can also be written as

$(x^2 -40) -41$

Therefore,

$(fog)(x) = (x^2 -40)-41$

$f(g(x)) = (x^2 -40)-41$

That gives,

$g(x) = x^2 -40, f(x) = x-41$

7 0

2 years ago

Can someone plss help me

puteri [66]

0/3 is the same thing as 0, so write those nxt to each other. Then 1/3, 2/3. Lastly 3/3 is the same as 1, so write those nxt to each other.

7 0

3 years ago

a class of 30 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 10 students each

Zolol [24]

Answer:

Step-by-step explanation:

It's given that 2 students borrowed 0 books, 12 borrowed 1 book, 10 borrowed 2 books, and 6 borrowed 3 or more books. The average of books per student is 2.

To analyse the problem, let a, b, c, d, e, and f be the number of books borrowed by each of the 6 students who borrowed 3 or more, as the maximum must be one of those 6.

The average is calculated by adding up the borrowed books from all students, and then diving it 30 (the number of students). This would be :

$\frac{2*0+12*1+10*2+(a+b+c+d+e+f)}{30} =2$

$\frac{32+(a+b+c+d+e+f)}{30} =2$

$\ 32+a+b+c+d+e+f=60$

$\ a+b+c+d+e+f=28$

The maximum value for any student would be found when all other 5 students borrowed the minimum, which is 3 in this case. So set them all but one equal to 3 :

$\ 3+3+3+3+3+f=28$

$\ 15+f=28$

$\ f=28 - 15=13$

So the maximum is 13.

7 0

3 years ago