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aleksklad [387]
3 years ago
13

Simplify ((1/x)-(1/y))/((1/x)+(1/y))

Mathematics
1 answer:
In-s [12.5K]3 years ago
7 0
<span>Simplify ((1/x)-(1/y))/((1/x)+(1/y))</span>


y-x
______

y+x
You might be interested in
12. How much do 21 bushels of sweet
lesantik [10]

Answer:

21 bushels of sweet corm weight 735 pounds.

Step-by-step explanation:

Given:

Weight of 21 bushels of sweet corn is obtained by multiplying the unit weight to the number of bushels required.

Unit weight of sweet corn is the weight of 1 bushel of sweet corn.

Weight of 1 bushel of sweet corn = 35 pounds

So, weight of 21 bushels of sweet corns = 35\times 21=735 pounds.

Therefore, 21 bushels of sweet corn weigh 735 pounds.

8 0
4 years ago
One month Yoko rented 3 movies and 5 video games for a total of $40. The next month she rented 9 movies and 7 video games for a
KATRIN_1 [288]

Answer:

  • movie: $3.75
  • video game: $5.75

Step-by-step explanation:

Two equations in two unknowns can be written:

  3m +5v = 40

  9m +7v = 74

These can be solved a variety of ways. One of them is using Cramer's rule. It tells you the solution to

  • ax +by = c
  • dx +ey = f

is given by ...

  • ∆ = bd -ea
  • x = (bf -ec)/∆
  • y = (cd -fa)/∆

For the numbers above,

  • ∆ = 5·9 -7·3 = 24
  • m = (5·74 -7·40)/24 = 90/24 = 3.75
  • v = (40·9 -74·3)/24 = 138/24 = 5.75

The rental cost for each movie is $3.75; for each video game, it is $5.75.

___

The attached graph shows a graphing calculator solution to these equations.

5 0
3 years ago
the arithmetic sequence ai is defined by the formula: a1 = -53 ai = ai-1 + 6 find the sum of the first 880 terms in the sequence
maxonik [38]

Answer:

The sum of the first 880 terms in the sequence is 2,273,920.

Step-by-step explanation:

Arithmetic sequence:

The difference between consecutive terms is always the same, called common difference, and the nth term is given by:

a_{n} = a_0 + (n-1)d

In which d is the common difference.

Sum of the first n terms:

The sum of the first n terms of an arithmetic sequence is given by:

S_{n} = \frac{n(a_1+a_n)}{2}

ai = ai-1 + 6

This means that d = 6

In this question:

Sum of the first 800 terms, so n = 800

First term is -53, so a_1 = -53

The 880th term is:

a_{880} = -53 + (880-1)*6 = 5221

Sum

S_{n} = \frac{880(-53+5221)}{2} = 440(-53+5221) = 2273920

The sum of the first 880 terms in the sequence is 2,273,920.

4 0
3 years ago
What’s the gcf of 18k and 15k cubed?
Contact [7]

Answer:

The GCF for the variable part is  

k

Step-by-step explanation:

Since  

18

k

,

15

k

3

contain both numbers and variables, there are two steps to find the GCF (HCF). Find GCF for the numeric part then find GCF for the variable part.

Steps to find the GCF for  

18

k

,

15

k

3

:

1. Find the GCF for the numerical part  

18

,

15

2. Find the GCF for the variable part  

k

1

,

k

3

3. Multiply the values together

Find the common factors for the numerical part:

18

,

15

The factors for  

18

are  

1

,

2

,

3

,

6

,

9

,

18

.

Tap for more steps...

1

,

2

,

3

,

6

,

9

,

18

The factors for  

15

are  

1

,

3

,

5

,

15

.

Tap for more steps...

1

,

3

,

5

,

15

List all the factors for  

18

,

15

to find the common factors.

18

:  

1

,

2

,

3

,

6

,

9

,

18

15

:  

1

,

3

,

5

,

15

The common factors for  

18

,

15

are  

1

,

3

.

1

,

3

The GCF for the numerical part is  

3

.

GCF

Numerical

=

3

Next, find the common factors for the variable part:

k

,

k

3

The factor for  

k

1

is  

k

itself.

k

The factors for  

k

3

are  

k

⋅

k

⋅

k

.

k

⋅

k

⋅

k

List all the factors for  

k

1

,

k

3

to find the common factors.

k

1

=

k

k

3

=

k

⋅

k

⋅

k

The common factor for the variables  

k

1

,

k

3

is  

k

.

k

The GCF for the variable part is  

k

.

GCF

Variable

=

k

Multiply the GCF of the numerical part  

3

and the GCF of the variable part  

k

.

3

k

3 0
3 years ago
A shipment of 23 television sets contain three defective ones. In how many ways can a vending machine purchase four of these uni
Alex_Xolod [135]
\frac{x}{y}  \frac{x}{y}  \frac{x}{y}  \frac{x}{y}  \frac{x}{y}  \neq  \sqrt{x}  \sqrt[n]{x}
4 0
3 years ago
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