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3 years ago

Why do objects repel and attract?

1 answer:

5 0

Objects repel and attract because of a thing called electrostatic attraction. When objects have the same charge (positive or negative), then they will repel, and if they have opposite charges then they will attract

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Un objeto que tiene como masa 80 kg acelera a razón de 10 m/s2 ¿que fuerza lo impulzo

Gemiola [76]

Answer:

What

Explanation:

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3 years ago

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A high fountain of water is located at the center of a circular pool. Not wishing to get his feet wet, a student walks around th

Alisiya [41]

Answer:

The fountain is 3.43 m high.

Explanation:

Circumference of the pool = 15 m.

C = 2 $\pi$ r

where C is the circumference and r its radius.

r = $\frac{C}{2\pi }$

= $\frac{15}{2(\frac{22}{7}) }$

r = 2.3864

radius of the pool = 2.40 m

So that the height of the fountain, h, can be determined by applying trigonometric function.

Tan θ = $\frac{opposite}{adjacent}$

Tan 55 = $\frac{h}{2.4}$

h = Tan 55 x 2.4

= 1.4282 x 2.4

= 3.4277

h = 3.43 m

The height of the fountain is 3.43 m.

8 0

3 years ago

A force of 6n is exerted on a cart that is carrying a rock and produces an acceleration of 2 m/s2. if the cart has a mass of 1 k

Alex777 [14]

F=ma
m=f/a
m=6N/2 m per secon per second
m=3 kg.
If the cart is 1 kg then 3kg-1kg is 2kg.
The mass of the rock is 2kg.

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4 years ago

What are formed by the outermost electrons

AlekseyPX

Answer:

Im sorry but i really need these points. FORGIVE ME

Explanation:

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3 years ago

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A 133 kg horizontal platform is a uniform disk of radius 1.95 m and can rotate about the vertical axis through its center. A 62.

cupoosta [38]

Answer:

The moment of inertia of the system is $I = 400.5 \ kg \cdot m^2$

Explanation:

From the question we are told that

The mass of the platform is $m = 133\ kg$

The radius of the platform is r = 1.95 m

The mass of the person is $m_p = 62.7 \ kg$

The position of the person from the center is $d = 1.19 \ m$

The mass of the dog is $m_D = 28.5 \ kg$

The position of the dog from the center is $D = 1.45 \ m$

Generally the moment of inertia of the platform with respect to its axis is mathematically represented as

$I_p = \frac{m r^2}{2}$

The moment of inertia of the person with respect to the axis is mathematically represented as

$I_z = m_p* d^2$

The moment of inertia of the dog with respect to the axis is mathematically represented as

$I_D = m_d * D^2$

So the moment of inertia of the system about the axis is mathematically evaluated as

$I = I_p + I_z + I_D$

=> $I = \frac{mr^2}{2} + m_p * d^2 + m_d * D^2$

substituting values

$I = \frac{(133) * (1.95)^2}{2} + (62.7) * (1.19)^2 + (28.5) * (1.45)^2$

$I = 400.5 \ kg \cdot m^2$

8 0

3 years ago