Answer:
none of the answers is correct, the time is the same t₁ = t₂ = 0.600 s
Explanation:
This is a kinematics exercise, analyze the situation a bit. The vertical speed in both cases is the same is zero, the horizontal speed in the second case is double (vₓ₂ = 2 vₓ₁)
let's find the time to hit the ground
y = y₀ + I go t - ½ g t²
0 = y₀ - ½ g t²
t = √ 2y₀ / g
with the data from the first launch
y₀i = ½ g t²
y₀ = ½ 9.8 0.6²
y₀ = 1,764 m
with this is the same height the time to descend in the second case is the same
t₂ = 0.600 s
this is because the horizontal velocity change changes the offset on the x axis, but does not affect the offset on the y axis
Therefore, none of the answers is correct, the time is the same
t₁ = t₂ = 0.600 s
Answer:
20654 N
Explanation:
Applying
F = kqq'/r²........... equation 1
Where F = Force between the charge, q = First charge, q' = second charge, r = distance betweeen the charge, k = coulomb's constant.
From the question,
Given: q = -0.0004 C, q' = 0.00092 C, r = 0.4 m
Constanr: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 1
F = ( -0.0004×0.00092×8.98×10⁹)/(0.4²)
F = (3.30464×10³)/0.16
F = (3304.64)/0.16
F = 20654 N
Hence the force between the charges is 20654 N
The objective in badminton is to hit the shuttle to the opponent's side of the court in a way that he/she is unable to return it. This is done by using various strokes such as net shot and smashes.
Hey! I’m not done yet! Let’s get to the facts.
WELL..... who made badminton?
Kenneth anijas soriano made the sport badminton in New York.
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