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PilotLPTM [1.2K]
3 years ago
7

Clouds of gas and dust as well as new star formation are typically seen in __________galaxy

Physics
1 answer:
ohaa [14]3 years ago
3 0

Answer:

Clouds of gas and dust as well as new star formation are typically seen in Spiral galaxy

Explanation:

The ingredients for star formation are gas and dust, a spiral galaxy is a group of stars that are together as a consequence of the gravitational pull between them and, as the name said it, has a spiral shape.

They are composed for a central bulge, a disk (in which a spiral arms structure can be seen), gas and dust. Because of the presence of gas and dust, star formation is possible.

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Use the dimensional analysis and check the correctness of given equation:- PV= nRT (no spam ) plz
gayaneshka [121]

Answer:

PV = nRT

n and R are constants.

Dimensions of Pressure = ML^-1T^-1

Volume dimensions = L³

(pressure)(volume) = (temperature) \\ (ML {}^{ - 1} T {}^{ - 2} )(L {}^{3} ) = (k) \\ ML {}^{2} T {}^{ - 2}  = k

It is dimensionally inconsistent or incorrect

7 0
2 years ago
Read 2 more answers
To understand the meaning of the variables that appear in the equations for rotational kinematics with constant angular accelera
Elis [28]

Answer:

   ω = ω₀ + α t

      ω² = ω₀² + 2 α  θ

      θ = θ₀ + ω₀ t + ½ α t²

Explanation:

Rotational kinematics can be treated as equivalent to linear kinematics, for this change the displacement will change to the angular displacement, the velocity to the angular velocity and the acceleration to the angular relation, that is

     x → θ

     v → ω

     a → α

with these changes the three linear kinematics relations change to

      ω = ω₀ + α t

      ω² = ω₀² + 2 α  θ

      θ = θ₀ + ω₀ t + ½ α t²

where it should be clarified that to use these equations the angles must be measured in radians

5 0
2 years ago
A 5.2 cm diameter circular loop of wire is in a 1.35 T magnetic field. The loop is removed from the field in 0.29 sec. Assume th
Katyanochek1 [597]

Answer:

9.88 milivolt

Explanation:

Given: diameter d = 5.2 cm

magnetic field B_1 = 1.35 T, final magnetic field B_2 =0 T

t = 0.29 sec.

we know emf =  - dΦ/dt

and flux Φ = BA

A= area

therefore emf ε = -A(B_2-B_1)/Δt

=-\pi(d/2)^2\frac{B_2-B_1}{\Delta t} \\=-\pi(0.052/2)^2\frac{0-1.35}{0.29} \\=98.8\times10^4\\=9.88 mV

3 0
3 years ago
Suppose a treadmill has an average acceleration of 4.7x10^-3 m/s. a)how much does its speed change after 5min? b)if the treadmil
Mars2501 [29]

Answer:

a)Change in the speed  = 1.41 m/s

b)The final speed will be 3.11 m/s

Explanation:

Given that

Acceleration ,a= 4.7 x 10⁻³ m/s²

a)

We know that

v= u + a t

v=final speed ,u=initial speed

t= time ,a= acceleration

Change in the speed

v- u = a t

t= 5 min  = 5 x 60 s = 300 s

v- u = 4.7 x 10⁻³ x 5 x 60 m/s

v-u = 1.41 m/s

Change in the speed  = 1.41 m/s

b)

Given that

u= 1.7 m/s

v-u = 1.41 m/s

v= 1.7 + 1.41 m/s

v=3.11 m/s

The final speed will be 3.11 m/s

8 0
3 years ago
If you know the answer please answer the following question down in the picture below.
Harlamova29_29 [7]
I think it’s the second one: magnetic domains must come in pairs—one north and one south
3 0
3 years ago
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