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cestrela7 [59]
3 years ago
5

A disk-shaped merry-go-round of radius 2.93 m and mass 135 kg rotates freely with an angular speed of 0.621 rev/s . A 62.4 kg pe

rson running tangential to the rim of the merry-go-round at 3.21 m/s jumps onto its rim and holds on. Before jumping on the merry-go-round, the person was moving in the same direction as the merry-go-round's rim.What is the final angular speed of the merry-go-round? rad/s
Physics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

2.55 rad/sec

Explanation:

Use conservation of angular momentum

The merry go round has

I = ½mr²

I = ½ * 135 * 2.93²

I = 579 kgm²

the person has

I = mr²

I = 62.4 * 2.93²

I = 536 kgm²

Converting 0.621 rev/sec to rad/sec we have 0.621 * 2π

0.621 * 2 * 3.14 rad/sec

3.9 rad/sec

for the person v/r = w

w = 3.21 / 2.93

w = 1.10 rad/sec

So

579 * 3.9 + 536 * 1.1 = (579+536)*w

2258 + 589.6 = 1115w

2847.6 = 1115w

solve for w

w = 2847.6 / 1115

w = 2.55 rad/sec

Thus, the final angular speed of the merry go round is 2.55 rad/sec

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Answer:

Explanation:

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r = mv / Be

2 ) If an electron is accelerated by an electric field created by potential difference V then electric field

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3 )

B = \frac{\mu\times I\times R^2}{2(R^2+Z^2)^\frac{3}{2} }

In Helmholtz coils , distance between coil is equal to R so Z = R/2

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For N turns of coil and total field due to two coils

B = \frac{\mu\times I\times N}{R\times(\frac{5}{4})^\frac{3}{2}  }

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8 0
4 years ago
Sagutin ang mga sumusunod na tanong. Isulat ang iyong sagot sa sagutang papel.
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Answer:

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3 years ago
An apple with mass 0.4 kg is hanging at rest from the lower end of a light vertical rope. A dart of mass 0.1 kg is shot vertical
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Answer:

The speed of the apple just after the collision is 1m/s

Explanation:

Since the two bodies collided, we will apply the law of conservation of momentum to find their common velocity which states that the sum of momentum of the bodies before collision is equal to the sum of momentum of the bodies after collision. After collision both bodies will move with a common velocity v.

Given momentum = mass × velocity

Initial momentum of the 0.4kg apple hanging at rest will be;

Momentum = 0.4kg×0m/s = 0kgm/s (the velocity of apple is 0m/s since it is hanging at rest)

Initial momentum of the 0.1kg dart moving with speed of 5m/s will be;

Momentum of dart = 0.1kg × 5m/s

Momentum of dart = 0.5kgm/s

Momentum of the bodies after collision will give;

Momentum after collision = (0.4kg+0.1kg) × v (v is their common velocity)

Momentum after collision = 0.5v

Using the law of conservation of momentum to calculate their common velocity, we will have;

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4 years ago
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Answer:

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Explanation:

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A = Surface area = 0.16 m²

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Converting to km/h

\frac{110.27}{1000}\times 3600=396.972\ km/h

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