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saul85 [17]
3 years ago
12

An automobile with a mass of 1240.00 kg has 3.99 m between

Physics
1 answer:
Vitek1552 [10]3 years ago
8 0

Answer:

948.15248\ N

5134.04751\ N

Explanation:

F_f = Force on front wheels

F_r = Force on rear wheels

Distance between CG and rear wheel = 3.99-0.622 = 3.368 m

F_r=1240\times 9.81-F_f

As the forces are conserved we have

(1240\times 9.81-F_f)3.368=F_f\times 0.622\\\Rightarrow 12164.4-F_f=\dfrac{0.622F_f}{3.368}\\\Rightarrow 12164.4-F_f=0.18467F_f\\\Rightarrow F_f=\dfrac{12164.4}{1.18467}\\\Rightarrow F_f=10268.09503\ N

On rear wheels

F_r=1240\times 9.81-10268.09503\\\Rightarrow F_r=1896.30497\ N

The force on each rear whees is \dfrac{1896.30497}{2}=948.15248\ N

Force on each front wheel is \dfrac{10268.09503}{2}=5134.04751\ N

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Answer:

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