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USPshnik [31]
3 years ago
13

What is the solution for -3x ≥ 36?

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0
Hey there!

To solve for the solutions of your inequality, divide both sides of your inequality by -3 in order to isolate the value of x:

-3x≥36
÷-3  ÷-3

x≤12 
**Note: in inequalities, if you ever divide or multiply a number that is negative, you must flip the inequality sign. In this case, because you have divided -3 from both sides, you must flip the inequality sign from ≥ to ≤.

Therefore, your solutions to your inequality would be x≤12.

Hope this helps, and have a nice day! :)
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A=0.8836

Step-by-step explanation:

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\frac{\pi r^2}{2}

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The NCAA is interested in estimating the difference in mean number of daily training hours for men and women athletes on college
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Answer:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data given

\bar X_M = 2.7 represent the sample mean for men

\bar X_F = 2.4 represent the sample mean for women

s_M = 0.3 represent the sample deviation for men

s_F = 0.4 represent the sample deviation for women

n_M = 10 sample size of male

n_F =10 sample size of women

The confidence interval is given by:

(\bar X_M -\bar X_F) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_M}+\frac{1}{n_F}}   (1)

The polled variance can be calculated with this formula:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

For a confidence of 95% the value for the significance is \alpha=1-0.95=0.05 and \alpha/2 = 0.025, the degrees of freedom are given by:

df = n_M + n_F -2= 10+10-2=18

And the critical value can be calculated with the following formula in excel: "=T.INV(1-0.025,18)" and we got t_{\alpha/2}=2.1

Now we can replace into the confidence interval:

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

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Answer:

4550 kilowatt

Step-by-step explanation:

Given that :

Amount of energy produced per hour by solar energy system = 9.1 kw per hour

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9.1 kw per hour * 5 hours = 45.5 Kilowatt per day

In 100 days :

Daily energy produced * number of days

45.5 kilowatt * 100 days

4550 kilowatt

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