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Artist 52 [7]
3 years ago
15

Determine how many mm of Hg are equal to 5.3 atm of pressure

Chemistry
1 answer:
MAVERICK [17]3 years ago
5 0
The answer is 4,028.0 mm of Hg

It is known that:
1 atm of pressure = 760.0 mm of Hg

Hence:
5.3 atm of pressure = x mm of Hg

Let's use the proportion:
1 atm : 760.0 mm Hg = 5.3 atm : x

After crossing the products:
x = 760.0 mm Hg * 5.3 atm : 1 atm
x = 4,028.0 mm of Hg

Therefore, 4,028.0 mm of Hg are equal to 5.3 atm of pressure
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“Representative elements”? Which groups of the periodic table contain the “representative elements”?
Phoenix [80]

S- and P-Block elements are known as Representative elements.

Groups 1-2 and Groups 13-18

4 0
3 years ago
1) If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?
sergey [27]

Answer:

204.8 K

Explanation:

We use the ideal gas equation:

PV = nRT

where R is the gas constant (0.082 L.atm/K.mol).

We have the following data:

n= 4 moles

P = 5.6 atm

V = 12 L

So, we introduce the data in the ideal gas equation to calculate the temperature (T):

T = PV/nR = (5.6 atm x 12 L)/(4 mol x 0.082 L.atm/K.mol) = 204.8 K ≅ -68 °C

6 0
2 years ago
Read 2 more answers
What is 5L to mL ( chemistry )
zlopas [31]

There are 1000 mililiters in a liter, so 1000 ml for every liter, you have 5 liters, so:

5L*1000 = 5000 mL

5 0
3 years ago
Read 2 more answers
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
You know that 8.9 moles of solute particles are dissolved in that liquid solution. If the molarity of the solution is 25 M, how
pychu [463]

Answer:

V = 0.356 L

Explanation:

In this case, we need to use the following expression:

M = n/V (1)

Where:

M: molarity of solution (mol/L or M)

n: moles of solute (moles)

V: Volume of solution (Liters)

From these expression, we can solve for V:

V = n/M  (2)

Now, replacing the given data we can solve V:

V = 8.9 / 25

V = 0.356 L

5 0
3 years ago
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