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Artist 52 [7]
3 years ago
15

Determine how many mm of Hg are equal to 5.3 atm of pressure

Chemistry
1 answer:
MAVERICK [17]3 years ago
5 0
The answer is 4,028.0 mm of Hg

It is known that:
1 atm of pressure = 760.0 mm of Hg

Hence:
5.3 atm of pressure = x mm of Hg

Let's use the proportion:
1 atm : 760.0 mm Hg = 5.3 atm : x

After crossing the products:
x = 760.0 mm Hg * 5.3 atm : 1 atm
x = 4,028.0 mm of Hg

Therefore, 4,028.0 mm of Hg are equal to 5.3 atm of pressure
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What is the atomic number of an atom that has 6 protons, 6 neutrons, and 6 electrons? quzket
Ivanshal [37]

The atomic number of an atom that has six protons, six neutrons, and six electrons is 6. And the element is carbon.

Carbon is known as a tetravalent compound.

It has four electrons in its outermost shell. It forms a covalent bond with other compounds.

The number of neutrons. = 6

Number of electrons = 6

Number of protons = 6

So the atomic number of the compound is,

The atomic number of an element = Number of protons present in its nucleus

The number of protons given in the compound is 6.

So the atomic number of the compound is also 6.

Carbon has six atomic numbers.

Therefore, the atomic number of an atom that has six protons, six neutrons, and six electrons is 6. And the element is carbon.

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brainly.com/question/1255220

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8 0
2 years ago
What is the volume of 9.5 g fluorine gas, F2, at STP?
Tju [1.3M]

Answer:

5.6L

Explanation:

At STP, the pressure and temperature of an ideal gas is

P = 1 atm

T = 273.15k

Volume =?

Mass = 9.5g

From ideal gas equation,

PV = nRT

P = pressure

V = volume

n = number of moles

R = ideal gas constant =0.082J/mol.K

T = temperature of the ideal gas

Number of moles = mass / molar mass

Molar mass of F2 = 37.99g/mol

Number of moles = mass / molar mass

Number of moles = 9.5 / 37.99

Number of moles = 0.25moles

PV = nRT

V = nRT/ P

V = (0.25 × 0.082 × 273.15) / 1

V = 5.599L = 5.6L

The volume of the gas is 5.6L

5 0
3 years ago
How many moles would be in 85.OmL of 0.750M KOH?
Harlamova29_29 [7]

Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Explanation:

Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity = 0.750 M

It is known that molarity is the number of moles of solute present in liter of a solution.

Therefore, moles present in given solution are calculated as follows.

Molarity = \frac{moles}{Volume (in L)}\\0.750 M = \frac{moles}{0.085 L}\\moles = 0.0637 mol

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

7 0
3 years ago
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