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levacccp [35]
3 years ago
5

If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct

ure Y---X---Y (2 lone pairs around X) could be abbreviated as XY2Z2. Classify these structures according to their shape.
Molecular Geometries:

linear

bent 120

bent 109

trigonal pyramidal

T-shaped

see saw

square planar

square pyramidal
Chemistry
1 answer:
Inessa05 [86]3 years ago
7 0

Answer:

The correct option is: bent 109°

Explanation:

Covalent molecules are the molecules in which the atoms are linked by covalent bonds. The electrons involved in the formation of a covalent bond are known as shared pair or <u>bond pair of electrons</u>.

The three-dimensional arrangement of the atoms of a molecule in space is known its molecular structure or geometry.

<u>Given molecule</u>: XY₂, having two lone pairs around the central atom X.

Since the molecule XY₂ has <u>two lone pairs</u> and <u>two bond pairs</u> of electrons. Therefore according to the VSEPR theory, the given molecule has a <u>bent molecular geometry with 109° bond angle.</u>

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Miguel’s family drove 357 miles on their weekend trip. Their car’s average gas mileage was 25.5 miles per gallon. How many gallo
ad-work [718]

Answer:

14 gallons

Explanation:

357 divided by 14 = 25.5 and if you check your answer 14 x 25.5 = 357 (i hope this is right)

6 0
2 years ago
Read 2 more answers
If 4.70 L of CO2 gas at 22 ∘C at 789 mmHg is used, what is the final volume, in liters, of the gas at 37 ∘C and a pressure of 75
lutik1710 [3]

Answer:

Final Volume = 5.18 Liters

Explanation:

Initial Condition:

P1 = 789 mm Hg x (1/760) atm /mm Hg = 1.038 atm

T1 = 22° C = 273 + 22 = 295 K

V1 = 4.7 L

Final Condition:

P2 = 755 mm Hg x (1/760) atm /mm Hg = 0.99 atm

T2 = 37° C = 273 + 37 = 310 K

V2 = ?

Since, (P1 x V1) / T1 =  (P2 x V2) / T2,

Therefore,

⇒ (1.038)(4.7) / 295 = (0.99)(V2) / 310

⇒ V2 = 5.18 L (Final Volume)

5 0
3 years ago
The bonds of four salts (MgBr2, NaCl, MgCl2, and NaBr) are evaluated for ionic character based on electronegativity differences
sammy [17]

Answer:

MgBr2 < MgCl2 < NaBr < NaCl

Explanation:

In order to determinate ionic character, we have to subtract the electronegativity from the elements involved. This is known as Pauling rule.

MgBr2 > ΔΕΝ = 1.8

NaCl > ΔΕΝ = 2.3

MgCl2 > ΔΕΝ = 2

NaBr > ΔΕΝ = 2.1

6 0
2 years ago
How many particles are in a 151 g sample of Li2O?
neonofarm [45]

Answer:

3.052 × 10^24 particles

Explanation:

To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)

The mass of Li2O given in this question is as follows: 151grams.

To convert this mass value to moles, we use;

moles = mass/molar mass

Molar mass of Li2O = 6.9(2) + 16

= 13.8 + 16

= 29.8g/mol

Mole = 151/29.8g

mole = 5.07moles

number of particles (nA) of Li2O = 5.07 × 6.02 × 10^23

= 30.52 × 10^23

= 3.052 × 10^24 particles.

4 0
2 years ago
What volume in liters of carbon monoxide will be required to produce 18.9 L of nitrogen in the reaction below
mina [271]

Answer:

37.8 L OF CARBON MONOXIDE IS REQUIRED TO PRODUCE 18.9 L OF NITROGEN.

Explanation:

Equation for the reaction:

2 CO + 2 NO ------> N2 + 2 CO2

2 moles of carbon monoxide reacts with 2 moles of NO to form 1 mole of nitrogen

At standard temperature and pressure, 1 mole of a gas contains 22.4 dm3 volume.

So therefore, we can say:

2 * 22.4 L of CO produces  22.4 L of N2

44.8 L of CO produces 22.4 L of N2

Since, 18.9 L of Nitrogen is produced, the volume of CO needed is:

44.8 L of CO = 22.4 L of N

x L = 18.9 L

x L = 18.9 * 44.8 / 22.4

x L = 18.9 * 2

x = 37.8 L

The volume of Carbon monoxide required to produce 18.9 L of N2 is 37.8 L

8 0
3 years ago
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