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Assoli18 [71]
2 years ago
10

Classify the following substances as an element,a mixture or a compound1.limestone​

Chemistry
1 answer:
vovangra [49]2 years ago
3 0

Answer: what’s your color. I wanna know oh oh oh

Explanation: Hahhhahhanahhahhajja

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“What is the group number for the elements that have a stable number of electrons in their outer energy level?”
Studentka2010 [4]

Answer:

A. 18

Explanation:

Sulfur number sixteen forms a negative

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3 0
2 years ago
Which of the following molecules is diamagnetic according to molecular orbital theory? A) N₂⁺ B) N₂⁻ C) CN D) CN⁻
Gnom [1K]

Answer:

D) CN⁻

Explanation:

    Hund's Rule of Maximum Multiplicity state that electrons go into degenerate orbitals of sub-levels (p,d, and f ) singly before pairing commences. Hund's rule is useful in determining the number of unpaired electrons in an atom. As such, it explains some magnetic properties of elements.

An element whose atoms or molecules contain unpaired electrons is paramagnetic. i.e., weakly attracted to substances in a magnetic field.

On the other hand, the element whose atoms or molecules are filled up with paired electrons is known as diamagnetic, i.e., not attracted by magnetic substances.

According to the molecular orbital theory, the diamagnetic molecule is CN⁻ because of the absence of unpaired electrons.

6 0
3 years ago
You are required to prepare 500 ml of a 6.00 M solution of HNO3 from a stock solution of 12.0 M. Describe in detail how you woul
andriy [413]

Answer: 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = concentration of stock solution = 12.0 M

V_1 = volume of stock solution = ?

C_2 = concentration of diluted solution= 6.00 M

V_2 = volume of diluted acid solution = 500 ml

Putting in the values we get:

12.0\times V_1=6.00\times 500

V_1=250ml

Thus 250 ml of stock solution with molarity of 12.0 M is measured using a pipette and 250 ml of water is added to volumetric flask of 500 ml to make the final volume of 500 ml.

8 0
2 years ago
What volume is occupied by 18.4 g oxygen at 28.0°C and a pressure of 0.998 torr? (round to sig figs)
Alexxandr [17]

Answer:

11.0 dm³

Explanation:

From the question,

Applying

PV= nRT............... Equation 1

Where P = pressure of oxygen gas, V = volume of oxygen gas, n = number of moles of oxygen, R = molar constant, T = Temperature.

make V the subeject of the equation

V = nRT/P............. Equation 2

But,

Number of mole (n) = Mass of oxygen(m)/Molar mass of oxygen(m')

n = m/m'....................... Equation 3

Substitute equation 3 into equation 2

V = mRT/Pm'............. Equation 4

Given: T = 28°C = (28+273) = 301 K, P = 0.998 torr = (0.998×0.00131579) = 1.3132 atm, m = 18.4 g

Constant: R = 0.082 atm.dm³/K.mol, m' = 32 g/mol.

Substitute these values into equation 4

V = (301×18.4×0.082)/(32×1.3132)

V = 454.1488/42.0224

V = 10.81 dm³

V = 11.0 dm³

8 0
2 years ago
Which of the following is an isotope of hydrogen​
Lena [83]
Z=1 is the formula i would have to see the following lol
7 0
2 years ago
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