N(CH₃OH)=3,62·10²⁴/6·10²³ 1/mol = 6,033 mol
m(CH₃OH) = 6,033 mol · 32 g/mol (molar mass) = 193,06 g.
Although you have not provided the circled electron, I can help you with a wide explanation.
1) Atomic number of manganese is 25. That means that it has 25 protons and 25 electrons.
2) Those 25 electrons are distributed (electron configuration) as per the quantum rules:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵
3) The most reasonable is that you have been asked to give the possible quantum numbers for an electron in the 4s or 3d.
4) Those are 7 electrons and these are their possible sets of quantum numbers:
i) For the two electrons in 4s:
n is the main energy level so n = 4
l tells the kind of orbital, which is s, so l = 0
ml is also 0 (it can be from -l to + l, so given that l i s0, ml is 0)
ms: one is +/12 and the other is -1/2 (this is the spin number).
ii) For the 5 electrons in 3d
n = 3
l can be 0, 1, or 2
if l = 0, then ml = 0
if l = 1, then ml can be -1, 0 , or 1 (from - l to + l)
ms can be either +1/2 or - 1/2 (spin)
Answer:
A: 1,2-dimethylcyclopropane
Explanation:
The possible cyclic structure with formula C₅H₁₀ are shown in the image.
A is a cyclic compound. On monochlorination, A yields 3 products.
To have 3 products on monochlorination, there should be three different carbon atoms.
Considering structure 1, all carbons have same nature, thus only one product will be formed and thus not a structure of A.
Considering structure 2, there are two different carbon atoms, thus two different structure are formed and thus not a structure of A.
Considering structures 3 and 4 , there are four different carbon atoms, thus four products will be formed and either of them are not a structure of A.
Considering structure 5, there are three different carbon atoms, thus three different structure are formed and thus the A is structure 5.
zero because its not going anywhere its stationary
hope this helped ^_^