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3 years ago

How to renamed fractions

1 answer:

Nutka1998 [239]3 years ago

6 0

The answer to this is

<span>Mixed Numbers to Fractions uses circle models to demonstrate how a number in mixed form can be renamed in fraction form. The illustration below was made by Mixed to Fraction with Circles Designer. It shows the mixed number 2 2/5. You are to write 2 2/5 in fraction form, with only a numerator and denominator.</span>

It is quite simple really
Hope It Helps

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There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one

diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

$P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02$

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01$

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05$

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C$

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0

4 years ago

I need answers ASAP!!

lesya [120]

What is the question?

7 0

3 years ago

Read 2 more answers

What is the solution set of {x | x < -3} ∩ {x | x > 5}

lozanna [386]

Any $x$ in this set will be real numbers that are both less than $-3$ and greater than $5$ . But that's not possible, so this set is empty.

7 0

3 years ago

There are 6 times as many dogs as cats. If total the total number of dogs and cats is 21, how many dogs are there?

artcher [175]

there are 18 dogs and 3 cats.

3 0

3 years ago

A water cup is shaped like a cone. It has a diameter of 3 inches and a slant height of 5 inches. About how many square inches of

daser333 [38]

Options were missing in the question;

A water cup is shaped like a cone. It has a diameter of 3 inches and a slant height of 5 inches. About how many square inches of paper do you need to make a cup? Use 3.14 to approximate pi.

24 square inches

31 square inches

47 square inches

52 square inches

Answer:

24 square inches

Step-by-step explanation:

Given:

Diameter = 3 in

So we can say that;

Radius is half of diameter.

radius (r) = $\frac{3}{2}=1.5\ in$

Slant height (l) = 5 in

We need to find how many square inches of paper do you need to make a cup.

Solution:

Now according to question we required to find the amount of paper used to make cup.

Also Water cup is shaped liked cone.

Hence we can say that the base of cone is not covered since it will remain open.

So we will use Lateral surface area of the cone to find the paper requirement.

Now we know that;

Lateral surface area of cone is equal to π times radius times slant height.

framing in equation form we get;

$A_L = \pi rl=3.14\times1.5\times5 = 23.55 in^2 \approx 24\ in^2$

Hence We can say that 24 square inches of paper will be needed to make the cup.

5 0

3 years ago