The factors are
(x-y)(x-y)
or
(x-y)^2
Explanation:
We need to factor the trinomial
x^2-2xy+y^2
The factors of x^2 = (x)(x)
The factors of y^2 = (y)(y)
Since the second sign is positive we are adding the factors meaning the signs of the factors need to be the same. Since the first sign is negative both signs must be negative.
The factors are
(x-y)(x-y)
or
(x-y)^2
Check by FOIL
Firsts (x)(x) = x^2
Outers (x)(-y) = -xy
Inners (-y)(x) = -xy
Lasts (-y)(-y) = y^2
combine the middle terms
(-xy)+(-xy) = -2xy
<span>x^2-2xy+y^2</span>
Answer:
1/72
Step-by-step explanation:
Answer: its rational since there is no irrational no in the denominator
Step-by-step explanation:
X = 2 +- √4 -32 )/2 = 1 +-i√7
Answer is <span>d. 1 plus i square root of 7
Hope it helps!
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BG ≅ AG
BG is the perpendicular to the side of the triangle while AG is the angle bisector , So BG cannot equal AG , So BG cannot be congruent to AG. Hence first is false.
DG ≅ FG
DG And FG both are the perpendicular to the sides from the incentre of the circle , Hence DG and FG are congruent , So second statement is true.
DG ≅ BG
Again DG and BG both are the perpendicular to the sides from the incentre of the circle , Hence DG and BG are congruent , So third statement is true.
GE bisects ∠DEF
As said in the question GE is the angle bisector , So yes GE bisects ∠DEF.
This Statement is true.
GA bisects ∠BAF
Again As said in the question GA is the angle bisector , So yes GA bisects ∠BAF.
Hence 2nd, 3rd , 4th , and 5th options are correct.
