Answer:
I'm going to paint you a picture in words of what this looks like on paper. We have a train leaving from a point on your paper heading straight west. We have another train leaving from the same point on your paper heading straight east. This is the "opposite directions" that your problem gives you.
Now let's make a table:
distance = rate * time
Train 1
Train 2
We will fill in this table from the info in the problem then refer back to our drawing. It says that one train is traveling 12 mph faster than the other train. We don't know how fast "the other train" is going, so let's call that rate r. If the first train is travelin 12 mph faster, that rate is r + 12. Let's put that into the table
distance = rate * time
Train 1 r
Train 2 (r + 12)
Then it says "after 2 hours", so the time for both trains is 2 hours:
distance = rate * time
Train 1 r * 2
Train 2 (r + 12) * 2
Since distance = rate * time, the distance (or length of the arrow pointing straight west) for Train 1 is 2r. The distance (or length of the arrow pointing straight east) for Train 2 is 2(r + 12) which is 2r + 24. The distance between them (which is also the length of the whole entire arrow) is 232. Thus:
2r + 2r + 24 = 232 and
4r = 208 so
r = 52
This means that Train 1 is traveling 52 mph and Train 2 is traveling 12 miles per hour faster than that at 64 mph
Step-by-step explanation:
Answer:
do you still need this answered?
Step-by-step explanation:
Answer: right triangle
Step-by-step explanation: 9, 40, and 41 are examples of Pythagorean triples.
Answer:
y = -1 - 2/1x
Step-by-step explanation:
Glad to help! :)
Answer:
sedan = 26 miles/gallon
truck = 17 miles/gallon
Step-by-step explanation:
try to write the text in mathematical format as a system of equations
t=truck s=sedan
first equation can be written as
t= (181-5s)/3
we can use it in the second equation and rewrite it as
7[(181-5s)/3]+6s = 275
7(181/3 -5/3s) + 6s = 275
1267/3 - 35/3s + 6s = 275
-35/3s + 18/3s = 275-1267/3
-35/3s + 18/3s = 825/3 - 1267/3
-35s + 18s = 825 -1267
-17s = -442 s = 442/17 = 26 sedan has an average of 26 miles/gallon
we use this value of s in the first equation
3t + 5*26=181 3t=181-130 t= 51/3 = 17 truck has an average of 17 miles/gallon
