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blsea [12.9K]
3 years ago
15

I’m confused on this one

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0
The answer is 42.

The question is asking for angle N. We know from the question that angle N is equal to angle E (Don't think about the scale factor because it only applies to the sides. They're just trying to trick you).

To find angle E:
79 + 6x + 11  + 7x - 14 = 180
Move numbers to the right side:
6x + 7x = 180 - 79 - 11 + 14
Combine like terms:
13x = 104
Divide both sides by 13:
x = 8
The formula for angle E:
7x - 14
Plug in the 8:
7 \times 8 - 14 = 56 - 14 = 42
The angle measure of E is 42. So angle N is automatically 42 too.

To solidify, we can try to use the formula which they give us for angle N:
3x + 18 = 24 + 18 = 42
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One week, Caroline earned $183.20 at her job when she worked for 8 hours. If she is paid the same hourly wage, how much would sh
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Answer:

$297.70

Step-by-step explanation:

First, find her hourly wage:

183.20/8

= 22.9

Then, multiply this by 13:

22.9(13)

= 297.7

So, she will make $297.70 next week

7 0
3 years ago
The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,
uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right).

We need to solve it and obtain an expression for P(t) in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right).

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that k=0.04 and K=500 and the initial condition P(0)=100.

Notice that this equation is separable, then

\frac{dP}{P(1-P/K)} = kdt.

Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}.

So,

\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|.

We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

Taking exponentials in both hands:

\left| \frac{K-P}{P}\right| = e^{-kt -C}

Hence,

\frac{K-P(t)}{P(t)} = Ae^{-kt}.

The next step is to substitute the given values in the statement of the problem:

\frac{500-P(t)}{P(t)} = Ae^{-0.04t}.

We calculate the value of A using the initial condition P(0)=100, substituting t=0:

\frac{500-100}{100} = A} and A=4.

So,

\frac{500-P(t)}{P(t)} = 4e^{-0.04t}.

Finally, as we want the value of t such that P(t)=200, we substitute this last value into the above equation. Thus,

\frac{500-200}{200} = 4e^{-0.04t}.

This is equivalent to \frac{3}{8} = e^{-0.04t}. Taking logarithms we get \ln\frac{3}{8} = -0.04t. Then,

t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325.

So, the population of rats will be 200 after 25 months.

6 0
3 years ago
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$8016.00

Step-by-step explanation:

I = 6000 × 0.042 × 8 = 2016

I = $ 2,016.00

$2,016.00 + $6,000.00 = 8,016.00

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Answer:

49

Step-by-step explanation:

7^2=49

3 0
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