The correct equation for the overall reaction can simply be obtained by adding the two separate equations together. Now when you add the two equations together, the overall K can be calculated by multiplying the individual K values. Therefore:<span>

K(overall) = K1 * K2 </span>

K(overall) = (1.6 x 10^-10) * (1.5 x 10^7)

<span>K(overall) = 2.4 x 10^-3</span>

3 0

3 years ago

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What is the balanced NET ionic equation for the reaction when aqueous Cs₃PO₄ and aqueous AgNO₃ are mixed in solution to form sol

rusak2 [61]

Answer:

$PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)$

Explanation:

Hello!

In this case, since the net ionic equation of a chemical reaction shows up the ionic species that result from the simplification of the spectator ions, which are those at both reactants and products sides, we take into account that aqueous species ionize into ions whereas liquid, solid and gas species remain unionized. In such a way, for the reaction of cesium phosphate and silver nitrate we can write the complete molecular equation:

$Cs_3PO_4(aq)+3AgNO_3(aq)\rightarrow Ag_3PO_4(s)+3CsNO_3(aq)$

Whereas the three aqueous salts are ionized in order to write the following complete ionic equation:

$3Cs^+(aq)+PO_4^{3-}(aq)+3Ag^+(aq)+3NO_3^-(aq)\rightarrow Ag_3PO_4(s)+3Cs^+(aq)+3NO_3^-(aq)$

In such a way, since the cesium and nitrate ions are the spectator ions because of the aforementioned, the net ionic equation turns out:

$PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)$

Best regards!

7 0

2 years ago

What volume will 20.0g of Argon occupy at STP?

Yuki888 [10]

Molar mass Argon = 39.948 g/mol

1 mol ------ 39.948 g
mol ----- 20.0 g

mol = 20.0 * 1 / 39.948

= 0.5006 moles

1 mol --------------------- 22.4 L ( at STP )
0.5006 moles ------------- L

L = 0.5006 * 22.4

= 11.21 L

hope this helps!

6 0

2 years ago

Vocabulary crossword puzzle properties of minerals

goblinko [34]

Answer: what were

Explanation:

4 0

2 years ago

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