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Marina CMI [18]
3 years ago
15

70.5 g C2H60 in 2.30 L of solution Please provide the answer in three significant figures

Chemistry
1 answer:
IgorLugansk [536]3 years ago
6 0

Answer:

http://www.learningaboutelectronics.com/Articles/Significant-figures-calculator.php?Articles/Significant-figures-sig-fig-calculator.php

Explanation:

I hope this helps!

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How many liters of 1.5 M HCl solution would react completely with 2.5 moles Ca(OH)2? (2 points)
mylen [45]
Here’s the math for your answer, which is 3.3 L HCl

6 0
3 years ago
Which of the following elements is likely to show additional stability in its electronic configurations because of filled and ha
kodGreya [7K]
Ah is gold and Rh is rhodium and Os is osmium and Ir iridium
3 0
2 years ago
Balance the following equations: (c) H2(g)+I2(s)⟶HI(s)H2(g)+I2(s)⟶HI(s)
kenny6666 [7]

Answer: H_2(g)+I_2(g)\rightarrow 2HI(s)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Thus in the reactants, there are 2 atoms of hydrogen and 2 atoms of iodine .Thus there has to be 2 atoms of hydrogen and 2 atoms of iodine in the product as well. Thus a coefficient of 2 is placed in front of HI.

The balanced chemical reaction is:

H_2(g)+I_2(g)\rightarrow 2HI(s)

6 0
3 years ago
Find the normality of 0.321 g sodium carbonate in a 250 mL solution.
Radda [10]

Answer:

the normality of the given solution is 0.0755 N

Explanation:

The computation of the normality of the given solution is shown below:

Here we have to realize the two sodiums ions per carbonate ion i.e.

N = 0.321g Na_2CO_3 × (1mol ÷ 105.99g)×(2eq ÷ 1mol)

= 0.1886eq ÷ 0.2500L

= 0.0755 N

Hence, the normality of the given solution is 0.0755 N

5 0
3 years ago
If you are supposed to put in 2/4 a cup sugar for a recipe, can you just put in a half cup of sugar?
natta225 [31]
I would assume so.

Given \frac{2}{4}, we can simplify the fraction to \frac{1}{2}

Both would obtain the same proportions, so I don't see why putting a half cup of sugar would make things any different.

Hope this is the answer you are looking for.
8 0
3 years ago
Read 2 more answers
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