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docker41 [41]
3 years ago
15

How do seismologists measure earthquakes?

Chemistry
1 answer:
choli [55]3 years ago
5 0

Answer:

A. By the circumference of the epicenter

Explanation:

If the Earth's lithospheric plates begin to move slowly, stresses emanate in the crust, most at times close to the plate boundaries. These stresses (compression, tension strain, and shear) accumulate in the crust until they surpass the rock's strength or the pressure around an internal fault. And there's a sudden slippage of rock around a fault.

The planet shakes and the rocks lurch to their new position in a matter of seconds as the stress energy is released. Seismic waves move away from the broken portion of the fault, just like ripples from a pebble landing on calm water.

Seismologists may estimate when the slippage started on a fault, the area of the slipping fault, the sum of slippage or fault throw (i.e. just how much the crust moved), and the length of time it takes for the slippage to happen by measuring the circumference of the epicenter which is the mapped area where the earthquake is taken place.

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Formulae for calculating number of moles​
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You would use this number, 6.02×1023 (Avogadro's number) to convert from particles, atoms, or molecules to moles. Whenever you go to the mole, divide by Avogadro's number. When you go to the unit from moles, multiply by Avogadro's number.
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What is the decay mode of radium-226?
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Answer:

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3 years ago
A 5.000 g mixture contains strontium nitrate and potassium bromide. Excess lead(II) nitrate solution is added to precipitate out
scZoUnD [109]

<u>Answer:</u> The mass percent of potassium bromide in the mixture is 9.996%

<u>Explanation:</u>

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

<u>For lead (II) bromide:</u>

Given mass of lead (II) bromide = 0.7822 g

Molar mass of lead (II) bromide = 367 g/mol

Putting values in equation 1, we get:

\text{Moles of lead (II) bromide}=\frac{0.7822g}{367g/mol}=0.0021mol

  • The chemical equation for the reaction of lead (II) nitrate and potassium bromide follows:

2KBr+Pb(NO_3)_2\rightarrow PbBr_2+2KNO_3

By Stoichiometry of the reaction:

1 mole of lead (II) bromide is produced from 2 moles of potassium bromide

So, 0.0021 moles of lead (II) bromide will be produced from = \frac{2}{1}\times 0.0021=0.0042mol of potassium bromide

  • Now, calculating the mass of potassium bromide by using equation 1, we get:

Molar mass of KBr = 119 g/mol

Moles of KBr = 0.0042 moles

Putting values in equation 1, we get:

0.0042mol=\frac{\text{Mass of KBr}}{119g/mol}\\\\\text{Mass of KBr}=0.4998g

  • To calculate the percentage composition of KBr in the mixture, we use the equation:

\%\text{ composition of KBr}=\frac{\text{Mass of KBr}}{\text{Mass of mixture}}\times 100

Mass of mixture = 5.000 g

Mass of KBr = 0.4998 g

Putting values in above equation, we get:

\%\text{ composition of KBr}=\frac{0.4998g}{5.000g}\times 100=9.996\%

Hence, the percent by mass of KBr in the mixture is 9.996 %

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what happens when baking soda is mixed with vinegar a a new substance is formed B the substances are the same c but the baking s
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Answer:

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Explanation:

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Move the decimal place to the left 3 digits.
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