In ΔAOD (AD) =(AO)
2+(OD)
2 =36+64 AD
2 =100
AD= 100
=10cm
Rhombus has all sides equal
AB = AD = BC = CD = 10 cm
The volume would be 201.06
Answer:
<em>Step-by-step explanation:</em>
<em>Step 1. (The capture) Capture a sample total counted =958, and them back tagged counted=38,total tagged=56
</em>
<em>The idea is to estimate the proportion p = m/N of tagged =102.
</em>
<em>Step 2. (The recapture) After everything has settled down, capture a new sample of n fish. Count the number of tagged fish. Suppose that k of them are tagged.
</em>
<em>It is reasonable that, k/n would be a good estimante for p = m/N.
</em>
<em>Accordingly, for an estimate N of N, se solve the equation m/N= k/n.
</em>