Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is 
The value for static friction is 
Explanation:
From the question we are told that
The mass of the clock is 
The first horizontal force is 
The second horizontal force is 
Generally the static frictional force is equal to the first horizontal force
So
=> 
=>
Generally the kinetic frictional force is equal to the second horizontal force
So
I believe the answer is a
Answer:
I thought "Born Without a Heart" was pretty good.
Hi
Explanation:
Answer:
2. ( b ) zero
3. ( c ) 10 s
4. Uniform then decreasing
Explanation:
2.
Since the motion is uniform, initial and final velocity will be 0, hence acceleration will be zero.
3.
Initial velocity ( u ) = 5 m/s
Final velocity ( v ) = 35 m/s
Acceleration ( a ) 3 m/s^2
To find : Time ( t )
Formula : -
t = v - u / a
= 35 - 5 / 3
= 30 / 3
t = 10 s
Answer:
20000 W
Explanation:
Power: This can be defined as the rate at which energy is dissipated or used. The S.I unit of power is Watt(W).
The expression of power is given as,
P = E/t.............................. Equation 1
Where P = power, E = Energy, t = time.
Given: E = 200 J, t = 0.01 s
Substitute into equation 1
P = 200/0.01
P = 20000 W.
Hence the average power = 20000 W
