The gravitational force between the two spheres is 0.006 N
Explanation:
The magnitude of the gravitational force between two objects is given by
where
is the gravitational constant
are the masses of the two objects
r is the separation between them
For the two spheres in this problem, we have
r = 2.55 m
Substittuting into the equation, we find
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Hello. This question is incomplete. The full question is:
Two blocks are stacked on top of each other on the floor of an elevator. For each of the following situations, select the correct relationship between the magnitudes of the two forces given.
The elevator is moving downward at a constant speed.
The magnitude of the force of the bottom block on the top block is _____ the magnitude of the force of the earth on the top block.
Answer:
The magnitude of the force of the bottom block on top block is equal to the magnitude of the force of the top block on bottom block.
Explanation:
As the elevator is descending, there is only a normal force being applied to the lower surface of the block. This force has a magnitude equal to the force of the upper block, because the only acceleration that is acting in this case is the force of gravity. From that force, the resulting force is zero.
Oh I’m so sorry rip winter
Answer:
I(x) = 1444×k ×
I(y) = 1444×k ×
I(o) = 3888×k ×
Explanation:
Given data
function = x^2 + y^2 ≤ 36
function = x^2 + y^2 ≤ 6^2
to find out
the moments of inertia Ix, Iy, Io
solution
first we consider the polar coordinate (a,θ)
and polar is directly proportional to a²
so p = k × a²
so that
x = a cosθ
y = a sinθ
dA = adθda
so
I(x) = ∫y²pdA
take limit 0 to 6 for a and o to 
for θ
I(x) = 
y²p dA
I(x) = (a sinθ)²(k × a²) adθda
I(x) = k 
da × 
(sin²θ)dθ
I(x) = k da × (1-cos2θ)/2 dθ
I(x) = k 
× 
I(x) = k × 
× ( 
I(x) = k × 
× 
I(x) = 1444×k × .....................1
and we can say I(x) = I(y) by the symmetry rule
and here I(o) will be I(x) + I(y) i.e
I(o) = 2 × 1444×k ×
I(o) = 3888×k × ......................2
U = I × R = 20A × 12 Ohm =240V
