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andreyandreev [35.5K]
3 years ago
12

The frequency of sound is 200 Hz. What does it mean? Please help me​

Physics
1 answer:
Norma-Jean [14]3 years ago
3 0

Explanation:

A wave having a frequency of 200 Hz means that 200 such waves pass through a point per second.

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Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance
scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

x_{1}=\dfrac{\lambda D}{2d}

Second minima from center

x_{2}=\dfrac{3\lambda D}{2d}

The distance between the places where the intensity is zero due to the double slit effect

\Delta x_{d}=x_{2}-x_{1}

\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}

\Delta x_{d}=\dfrac{\lambda D}{d}

Put the value into the formula

\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}

\Delta x_{d}=0.015 =15\times10^{-3}\ m

\Delta x_{d}=15\ mm

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

8 0
3 years ago
A diamond is underwater; A light ray enters one face of the diamond, then travels at an angle of 30 degrees with respect to the
otez555 [7]
According to snells law 

<span>n1 sin theta1 = n2 sin theta2
</span>n1  = 1.333 (water)
<span>n2  = 2.42 (diamond)</span>
 it is given that theta =30 degrees so 
by putting the values we have 

<span>1.333 sin theta = 2.42 sin 30 </span>

<span>sin theta = (2.42/1.333) *0.5 =65.2 degree
</span>so our conclusion is 

<span>the ray's angle of incidence θ1 on the diamond</span> = 65.2 degree.
hope this helps
4 0
3 years ago
Two workers are sliding 350 kgkg crate across the floor. One worker pushes forward on the crate with a force of 390 NN while the
svetoff [14.1K]

Answer:

\mu_k=0.18

Explanation:

First, we write the equations of motion for each axis. Since the crate is sliding with constant speed, its acceleration is zero. Then, we have:

x: T+F-f_k=0\\\\y:N-mg=0

Where T is the tension in the rope, F is the force exerted by the first worker, f_k is the frictional force, N is the normal force and mg is the weight of the crate.

Since f_k=\mu_k N and N=mg, we can rewrite the first equation as:

T+F-\mu_k mg=0

Now, we solve for \mu_k and calculate it:

\mu_k=\frac{T+F}{mg}\\ \\\mu_k =\frac{220N+390N}{(350kg)(9.8m/s^{2})} =0.18

This means that the crate's coefficient of kinetic friction on the floor is 0.18.

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What is the definition of chemical change
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