<span>0.0157 L.
For this equation use the combined gas law, which states P1*V1/T1 = P2*V2/T2, but in this case we can remove the T, because T1 = T2, because the temperature is constant. Then we solve for V2 because it is the new volume. So
P1*V1/P2 =V2
Plug in the variables, P1 = 100 atm, V1 = 1.02 L, P2 = 65.0 atm, and V2 = 0.0157 atm.</span>
Mass spectrum of Dodecane will give following information.
1 ) Molecular Peak or Parent Peak:
The Parent peak will appear at m/z = 170. The intensity of this peak will be very weak.
2) Fragments:
Usually the fragments of such long chain alkanes appear with spacing of 14 amu, Hence, the peaks in dodecane will be as follow,
170 - 156 - 142 - 128 - 114 - 100 - 86 - 72 - 58 - 44 - 30 - 16
3) Base Peak:
Most probably the Base peak will appear at m/z = 57. This peak is due to the formation of tertiary butyl cation as the intensity mainly depends upon the stability of cation. So this cation might form due to rearrangment giving the intensity of 100%.
Answer:
49.54%
Explanation:
Given parameters:
Number of organisms in original habitat = 4695
Number of organism in new habitat = 2326
Solution:
To find the percentage of the organisms in the new habitat that has migrated to the new habitat, we use the expression below:
% of the population in the new habitat = x 100
% of the population in the new habitat = x 100 = 49.54%
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Answer:
Compound.
Explanation:
That would be compound as it consists of a number of elements bonded together. It is inorganic not organic.
