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agasfer [191]
4 years ago
10

If this reaction produced 19.6 g of kcl, how much o2 was produced (in grams)?

Chemistry
1 answer:
stepladder [879]4 years ago
4 0
Answer is: mass of oxygen is 12,576 grams.
Missing chemical reaction: 2KClO₃ → 2KCl + 3O₂.
m(KCl) = 19,6 g.
n(KCl) = m(KCl) ÷ M(KCl).
n(KCl) = 19,6 g ÷ 74,55 g/mol.
n(KCl) = 0,262 mol.
From chemical reaction: n(KCl) : n(O₂) = 2 : 3.
n(O₂) = 3 · 0,262 mol ÷ 2.
n(O₂) = 0,393 mol.
m(O₂) = n(O₂) · M(O₂).
m(O₂) = 0,393 mol · 32 g/mol.
m(O₂) = 12,576 g.

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A gas at constant temperature has a pressure of 404.6 kPa with a volume of 12 ml. If the volume changes to 43ml, what is the new
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The answer is

<h2>112.912 kPa</h2>

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3 years ago
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The amount is x  =  113.3 \  dollars

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     The car's  gas mileage is  b =  22.0 \ mi/gal

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=>    k  = \frac{ 474.18}{ 22}

=>      k  =  22 \ gal

converting to liters

          k =  22 *  3.78541=83.28 \ liters

Thus the amount spent on gas in one week is  

          x =  k *  c

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