Answer: Temperature is an example of a quantitative variable
Explanation:
A quantitative variable is defined as :
- A variable that can assume a numerical value .
 - It can be ordered with respect to either magnitude or dimensions.
 - It is further classified into two types : interval scale and ratio scale.
 
Temperature comes under interval scale , because interval scale has no zero point.
For example : A 0° C Celsius does not interpret that there is no temperature.
Therefore , Temperature is an example of a quantitative variable.
Hence, the correct answer is "quantitative variable"
 
 
        
             
        
        
        
Answer: Ok I think The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Carbon, or 12.0107 grams. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between moles Carbon and gram. 12 grams
This means that the atomic mass or atomic weight (12 grams) of carbon is equal to exactly 1 mole of carbon.
hope this helps have a awesome night/day❤️✨
Explanation:
 
        
             
        
        
        
Answer:
Because of the less reactivity of copper.
Explanation:
 As well as being resistant to the elements and thereby less likely to be affected by rainfall, hail, and mildew than other types of roofing, copper is also one of the most fireproof materials available. Copper is also highly resistant to thermal changes and thereby doesn't deteriorate quickly.
Magnesium would also corrode PDQ. Magnesium sheeting would also pose an unacceptably high fire hazard.
 
        
             
        
        
        
kinetic energy is a moving object potential energy is stored energy
        
                    
             
        
        
        
The molar mass of the gas is 77.20 gm/mole.
Explanation:
The data given is:
P = 3.29 atm,   V= 4.60 L   T= 375 K  mass of the gas = 37.96 grams
Using the ideal Gas Law will give the number of moles of the gas. The formula is 
PV= nRT    (where R = Universal Gas Constant 0.08206 L.atm/ K mole
Also number of moles is not given so applying the formula
n= mass ÷ molar mass of one mole of the gas.
n = m ÷ x   ( x  molar mass) ( m mass given)
Now putting the values in Ideal Gas Law equation
PV = m ÷ x RT
3.29 × 4.60 = 37.96/x × 0.08206 × 375
15.134 = 1168.1241  ÷ x
15.134x = 1168.1241
x = 1168.1241 ÷ 15.13
x = 77.20 gm/mol
If all the units in the formula are put will get cancel only grams/mole will be there. Molecular weight is given by gm/mole.