There are zero lone pairs of electrons on the central carbon atom in a Lewis Structure of CHI3. The correct option is b.
Explanation:
Lone pair electrons are those valence electrons of an atom which do not take part in bonding or left after the bonds are formed.
CH
carbon is the central atom in the compound having 4 valence electrons.
Each iodine molecule has 7 valence electrons.
H has 1 valence electron.
from the Lewis structure of CH
, it is seen that all four valence electrons of the carbon is involved in bonding with 3 atoms of iodine and 1 atom of hydrogen.
Thus when all valence electrons are involved in bonding no lone pair of electron is found in CH
that means zero lone pairs of electrons.
The octet of the iodine, carbon and hydrogen gets completed to form the compound.
0.019 Hope this helps! :)
The balanced equation for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃<span>OH(g)
Since given concentrations are at equilibrium state, the expression for the equilibrium constant, k can be written as
k = [</span>CH₃OH(g)] / [CO(g)] [H₂(g) ]²
By substitution,
k = 0.030 M / 0.020 M x (<span>0.072 M</span>)²
k = 289.35 M⁻²
O2 gas, where there are two Oxygen atoms which are covalently bonded together