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Klio2033 [76]
4 years ago
6

Which process is used to produce gases from solutions of salts dissolved in water or another liquid?

Chemistry
1 answer:
Aleksandr-060686 [28]4 years ago
8 0

Answer:

A.Electrolysis

Explanation:

A.Electrolysis

For example,  electrolysis of solution of NaCl in water gives H2 and O2.

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If the pressure of a gas is 100 kPa when the volume is measured to be 500 mL. What pressure would need to be exerted to have the
Korvikt [17]

Answer:

p2=125 kpa

Explanation:

Using Boyle's law

p1 x v1 = p2 x v2

p1=100kpa

v1=500ml

p2=?

v2=400ml

p2= (100x500)\400

p2=125 kpa

:)

8 0
4 years ago
In the reaction below, 22 g of H2S with excess
BartSMP [9]

Answer:

24%

Explanation:

From the question, the limiting reactant is H2S.

The reaction equation is;

2H2S + O2 → 2S + 2H2O

Number of moles of H2S reacted = 22g/34 g/mol = 0.647 moles

According to the reaction equation;

2 moles of H2S yields 2 moles of sulphur

0.647 moles of H2S yields 0.647 moles of sulphur

So;

Theoretical yield of sulphur = 0.647 moles * 32 g/mol = 20.7 g

Actual yield = 5 g

% yield = actual yield/theoretical yield * 100

% yield =5 g/20.7 g * 100

% yield = 24%

7 0
3 years ago
If the NaOH is added to 35.0 mL of 0.167 M Cu(NO3)2 and the precipitate isolated by filtration, what is the theoretical yield of
Ghella [55]

Answer:

The correct answer is - 0.570 grams

Explanation:

The balanced chemical reaction is given by

Cu(NO3)2(aq)     + 2NaOH(aq)    -------->    Cu(OH)2(s)      + 2NaNO3(aq)

        1.0 mole            2.0 mole                 1.0 mole          2.0 mole

number of mol of Cu(OH)2,

n = Molarity * Volume

= 35.0*0.167 = 5.845 millimoles

As clear in the equation, 1 mole of Cu(NO3)2 gives 1 mole of Cu(OH)2 , So, 5.845 millimoles of Cu(NO3)2 will produce 5.845 millimoles of Cu(OH)2

Mass of Cu(OH)2 = number of mol * molar mass

= 97.5*5.845*10^-3

= 0.570 grams

Thus, the correct answer is - 0.570 grams

8 0
3 years ago
Question 1
slamgirl [31]

Answer:

Fossil record

Explanation:

but first think about it befor you do so it could be wrong im not a computer

7 0
3 years ago
Refer to the following parallel circuit:
Airida [17]

Answer:

6.93

Explanation:

correct me if verry wrong

6 0
3 years ago
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