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Liono4ka [1.6K]
2 years ago
14

a natrual distsater caused a population of 4,695 organisms to migrate to a new habitat. a few generations after the disaster it

was observed that the new habitat did not sopport the survival of the species. the table shows the population of the species in two habitats
Chemistry
1 answer:
Scilla [17]2 years ago
7 0

Answer:

49.54%

Explanation:

Given parameters:

Number of organisms in original habitat = 4695

Number of organism in new habitat = 2326

Solution:

To find the percentage of the organisms in the new habitat that has migrated to the new habitat, we use the expression below:

% of the population in the new habitat =  x 100

% of the population in the new habitat =  x 100 = 49.54%

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A sample of hydrogen gas at a pressure of 0.926 atm and a temperature of 29.5 C, occupies a volume of 457 mL. If the gas is allo
klio [65]

Answer:

V₂ = 946.72 mL

Explanation:

Given data;

Initial pressure = 0.926 atm

Initial volume = 457 mL

Temperature = constant = 29.5°C

Final pressure = 0.447 atm

Final volume = ?

Solution:

The given problem will be solved through the Boyle's law,

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

by putting values,

P₁V₁ = P₂V₂

0.926 atm × 457 mL = 0.447 atm × V₂

V₂ = 423.18 atm. mL/ 0.447 atm

V₂ = 946.72 mL

4 0
3 years ago
Which of the following factors is the most in-<br> fluential in the formation of soil?
Shtirlitz [24]
B. climate
this is because it influences the speed of chemical reactions in the soil







4 0
3 years ago
How scientists used the scientific method to learn more about how dinosaurs became extinct​
lesya [120]

Answer:

they tested the bone age

Explanation:

4 0
3 years ago
What is the density of a liquid if it's volume is 125 mL and it's mass is 50g?
masha68 [24]

Answer:

0.4g/ml

Explanation:

density= mass/volume

density=50g/125ml

density=0.4g/ml

6 0
3 years ago
In methane combustion, the following reaction pair is important: At 1500 K, the equilibrium constant Kp has a value of 0.003691
andre [41]

Explanation:

Let us assume that the value of K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{T}}) m^{6}/mol^{2}s

Also at 1500 K, K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{1500}}) m^{6}/mol^{2}s

                     K_{r} = 400.613 m^{6}/mol^{2}s

Relation between K_{p} and K_{c} is as follows.

                  K_{p} = K_{c}RT

Putting the given values into the above formula as follows.

                  K_{p} = K_{c}RT

         0.003691 = K_{c} \times 8.314 \times 1500

                K_{c} = 2.9 \times 10^{-7}

Also,     K_{c} = \frac{K_{f}}{K_{r}}

or,                K_{f} = K_{c} \times K_{r}

                               = 2.9 \times 10^{-7} \times 400.613

                               = 1.1617 \times 10^{-4} m^{6}/mol^{2}s

Thus, we can conclude that the value of K_{f} is 1.1617 \times 10^{-4} m^{6}/mol^{2}s.

6 0
3 years ago
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