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Ann [662]
3 years ago
7

Brian is given an unknown element that is bright when sunlight hits it. He has a hammer and an electrical source. If he attached

the electrical source, what might happen if the substance is a metalloid?
Physics
2 answers:
vodka [1.7K]3 years ago
6 0

Answer: We know that the material has a bright when sunlight hits it, now we connect an electricl source to our material, which implies that we may have a current in it.

Metalloids are materials between metals and non-metals, and one way to differentiate them of the metals is by the fact that metalloids are semi-conductors (and normal metals are conductors)

This would mean that a current flowing in a metalloid will "dissipate" faster than if it flowed in a metal.

And one interesting thing about them is that if you increase the temperature of the metalloid the electrical conductivity also does increase.

Answering the question, with the source attached to the metalloid, we will have current flow, but the reading (amperage) should show that the total current decreases, and we also may see an increase in the temperature of the material (it heats when the electrons flowing inside of it stop moving, for example, because a collision)

ikadub [295]3 years ago
4 0
Metalloids are between metals and non-metals. Metals conduct electricity while Non-metals do not. Since metalloids are somewhere in between, then the substance may conduct some electricity. Hope it helps.
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A single sports fan is capable of yelling at an intensity level of 80 decibels from a given distance. If 10,000 similar fans wer
AleksandrR [38]

Answer:

The correct answer is part 'c' 160 dB

Explanation:

When noise levels of different intensities are superimposed the resultant intensity is given by the equation

L_{avg}=20log(\frac{1}{N}\sum_{i=1}^{N}(10^{\frac{L_{i}}{20}}))\\

where,

L_{i} is the intensity of a general sound level

Since we have 10000 fans each producing sound of 80dB thus the resultant intensity is given using the above formula as

L_{avg}=20log(\frac{1}{10000}\sum_{i=1}^{10000}(10^{\frac{80}{20}}))\\

\therefore L_{eq}=160dB

7 0
3 years ago
A massless rod is attached to the ceiling by a string. Two weights are hung from the rod: a 0.4-lb weight at its left end and a
user100 [1]

The tension in the string supporting the rod and the attached weights is 7.11 N.

<h3>Tension in the string supporting the rod</h3>

The tension in the string supporting the rod and the attached weights is the sum of the weights supported by the strings.

T = (m1 + m2)g

where;

  • m1 and m2 are the two masses supported

0.4lb + 1.2lb = 1.6lb = 0.725 kg

T = 0.725 x 9.8

T = 7.11 N

Learn more about tension here: brainly.com/question/918617

#SPJ1

7 0
2 years ago
12)
Nataliya [291]

Answer: b

Explanation: the two pieces will repel as both have obtained a static charge.

5 0
3 years ago
1.How many significant digits are in 101,407,063?
Nataliya [291]

Answer:

= 9

Explanation:

just count the numbers :D

4 0
3 years ago
When a system is heated, heat is _______________ by the system. The amount of heat added is given a _______________ sign. When a
Valentin [98]

First of all, we need to write the First Law of thermodynamics assigning the correct sign convention:

\Delta U = Q+W

where

\Delta U is the change in internal energy of the system

Q is the heat absorbed/released

W is the work done

and the signs are assigned based on whether there is an increase in the internal energy or not. Therefore:

Q is positive if it is absorbed by the system (because internal energy increases)

Q is negative if it is released by the system (because internal energy decreases)

W is negative if it is done by the system on the surrounding (because internal energy decreases)

W is positive if it is done by the surrounding on the system (because internal energy increases)

Using these definitions, we can now fill the text of the question:

When a system is heated, heat is ABSORBED by the system. The amount of heat added is given a POSITIVE sign. When a system is cooled, heat is RELEASED by the system. The amount of heat is given a NEGATIVE sign. If a gas expands, it must push the surrounding atmosphere away. Thus, work is done BY the system and is given a NEGATIVE sign. If a gas is compressed, then work is done ON the system. This work is given a POSITIVE sign.

7 0
3 years ago
Read 2 more answers
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