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Ann [662]
3 years ago
7

Brian is given an unknown element that is bright when sunlight hits it. He has a hammer and an electrical source. If he attached

the electrical source, what might happen if the substance is a metalloid?
Physics
2 answers:
vodka [1.7K]3 years ago
6 0

Answer: We know that the material has a bright when sunlight hits it, now we connect an electricl source to our material, which implies that we may have a current in it.

Metalloids are materials between metals and non-metals, and one way to differentiate them of the metals is by the fact that metalloids are semi-conductors (and normal metals are conductors)

This would mean that a current flowing in a metalloid will "dissipate" faster than if it flowed in a metal.

And one interesting thing about them is that if you increase the temperature of the metalloid the electrical conductivity also does increase.

Answering the question, with the source attached to the metalloid, we will have current flow, but the reading (amperage) should show that the total current decreases, and we also may see an increase in the temperature of the material (it heats when the electrons flowing inside of it stop moving, for example, because a collision)

ikadub [295]3 years ago
4 0
Metalloids are between metals and non-metals. Metals conduct electricity while Non-metals do not. Since metalloids are somewhere in between, then the substance may conduct some electricity. Hope it helps.
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A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field. A deuteron has the same char
Yuri [45]

Answer:

The ratio of the acceleration of the proton to that of the deuteron is 2

Explanation:

For a moving charge in magnetic field, the magnetic force is balanced by force due to its motion. So,

qvB=ma

Acceleration of proton,

a_p=\dfrac{qvB}{m_p}  .........(1)

Acceleration of deuteron,

a_d=\dfrac{qvB}{m_d}   ..........(2)

Since, a deuteron has the same charge as the proton but has twice its mass.

Dividing equation (1) and (2) we get :

\dfrac{a_p}{a_d}=\dfrac{m_d}{m_p}

m_d=2m_p

\dfrac{a_p}{a_d}=\dfrac{2m_p}{m_p}\\\\\dfrac{a_p}{a_d}=2

So, the ratio of the acceleration of the proton to that of the deuteron is 2. Hence, the correct option is (a).

4 0
3 years ago
What’s the opposite of an electron
Anna007 [38]
As its charge, proton -a positive charged molecule at the center of an atom- is the opposite of the electron -the particle which is orbiting the center of an atom.
7 0
4 years ago
john gottman, the eminent marriage counselor put the number of conflicts which cannot be resolved and needed to be worked on con
USPshnik [31]
He called the counterproductive.
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3 years ago
Un automóvil viaja a la velocidad de 10 m/s. Se acelera Durante 12s y aumenta su velocidad hasta 70 m/s ¿Que aceleración experim
VladimirAG [237]

Answer:

Aceleracion = 5 m/s²

Explanation:

Dados los siguientes datos;

Velocidad inicial = 10 m/s

Velocidad final = 70 m/s

Tiempo, t = 12 segundos

Para encontrar la aceleración;

Aceleración se puede definir como la tasa de cambio de la velocidad de un objeto con respecto al tiempo.

Esto simplemente significa que la aceleración viene dada por la resta de la velocidad inicial de la velocidad final a lo largo del tiempo.

Por lo tanto, si restamos la velocidad inicial de la velocidad final y la dividimos por el tiempo, podemos calcular la aceleración de un objeto. Matemáticamente, la aceleración viene dada por la fórmula;

Aceleracion = \frac{final \; velocidad  -  inicial \; velocidad}{tiempo}

Sustituyendo en la fórmula, tenemos;

Aceleracion = \frac{70 - 10}{12}

Aceleracion = \frac{60}{12}

Aceleracion = 5 m/s²

8 0
3 years ago
Point charge A is located at point A and point charge B is at point B. Points A and B are separated by a distance r. To determin
fredd [130]

Answer:

B. The algebraic sum of the two electric potentials is determined at a distance r/2 from each of the charges, making sure to include the signs of the charges.

Explanation:

Total electric potential is the sum of all the electric potential. And because electric potential is a scalar quantity you have to account for the signs.

3 0
3 years ago
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