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barxatty [35]
2 years ago
10

The oscillation of the 2.0-kg mass on a spring is described by x = 3.0 cos (4.0 t) where x is in centimeters and t is in seconds

. What is the force constant k of the spring?

Physics
1 answer:
jeka57 [31]2 years ago
7 0
X is the answer because x can be any thing
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How much potential energy is stored on a stone kept on the earth surface? Why?​
olga2289 [7]

Answer:

When the body is kept at the surface there height of the stone is equal to zero. hence, if the height of the stone is zero then Potential energy is equal to zer

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3 years ago
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A car accelerates from rest. It reaches a velocity of 25m/s in 10 seconds. What was the cars acceleration?
mixer [17]

Answer:

We are Given:

initial velocity (u) = 0m/s

final velocity (v) = 25 m/s

time (t) = 10 seconds

acceleration (a)  = a m/s/s

From the first equation of motion, we know that:

v = u + at

solving for a, we get:

a = (v-u) / t

now, plugging the given values in this equation

a = (25 - 0) / 10

a = 25 / 10

a = 2.5 m/s/s

Therefore, the acceleration of the car is 2.5 m/s/s

3 0
3 years ago
Paco was driving his scooter west with an initial velocity of 4 m/s. He accelerates at 0.5 m/s2 for 30 seconds.
KonstantinChe [14]

Answer:

V = 19m/s

Explanation:

Given the following data;

Initial velocity, U = 4m/s

Acceleration, a = 0.5m/s²

Time, t = 30 seconds

To find the final velocity, we would use the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

V = 4 + 0.5*30

V = 4 + 15

V = 19m/s

Therefore, his final velocity is 19 meters per seconds.

6 0
3 years ago
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A string attached to an airborne kite is maintained at an angle of 41 degrees with the horizontal. If a total of 152 m of string
satela [25.4K]

Answer:

The  horizontal displacement is  Adj  =  114.71 \ m

Explanation:

From the question we are told that  

    The  angle at which the string is maintained is  \theta  =  41 ^o

      The length of string reeled in is  l  = 152 \ m

     

Using the SOHCAHTOA formula

   We have that the hypotenuse(Hyp) is  l  =  152

Hence the  horizontal displacement of the kite  which is the Adjacent(Adj)  can be evaluated as  

     cos \theta  =  \frac{Adj}{Hyp }

substituting values

     cos(41)  =  \frac{Adj}{152}

=>   Adj  =  114.71 \ m

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3 years ago
Converging trade winds produce a calm region called
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B. Doldrums. I cant actually explain it i just know its the answer
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