Answer:
Explanation:
1 ) tire of radius 0.381 m rotating at 12.2 rpm
12.2 rpm = 12.2 /60 rps
n = .20333 rps
angular speed
= 2πn
= 2 x 3.14 x .20333
= 1.277 rad / s
2 ) a bowling ball of radius 12.4 cm rotating at 0.456 rad/s
angular speed = .456 rad/s
3 ) a top with a diameter of 5.09 cm spinning at 18.7∘ per second
18.7° per second = (18.7 / 180) x 3.14 rad/s
= .326 rad/s
4 )
a rock on a string being swung in a circle of radius 0.587 m with
a centripetal acceleration of 4.53 m/s2
centripetal acceleration = ω²R
ω is angular velocity and R is radius
4.53 = ω² x .587
ω = 2.78 rad / s
5 )a square, with sides 0.123 m long, rotating about its center with corners moving at a tangential speed of 0.287 m / s
The radius of the circle in which corner is moving
= .123 x √2
=.174 m
angular velocity = linear velocity / radius
.287 / .174
1.649 rad / s
The perfect order is
4 ) > 5> 1 >2>3.
Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder. ... The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less.
Answer:
Therefore, the car will cover a distance of 200 meters after 10 seconds.
<h2>
Please mark me as brainliest</h2>
Answer:
t = 1.09 s.
Explanation:
This is a one-dimensional kinematics question, so the equations of kinematics will be sufficient to solve the question.
This quadratic equation can be solved using determinant.
Of course, we will choose the positive time.
Answer:
F = 91.27 N
Explanation:
Parameters given:
Charge of alpha particle, q = +2.0e = 
= 
Charge of gold nucleus, Q = +79e = 
= 
Distance between the alpha particle and gold nucleus, r = 
Electric force is given as:
F = 
where k = Coulomb's constant
Therefore:
The electric force acting on the alpha particle when the alpha particle is from the gold nucleus is 91.27 N.
