The average useful power output of robot is 0.0001 W
The time taken by robot to lift bricks is 630000000 sec
Given:
work done by robot = 5.5 j
time taken to do the work = 12.0 hours
weight of bricks = 3500 kg
length of bricks = 1.8 m
To Find:
The average useful power output of robot is
The time taken by robot to lift bricks is
Solution: Useful power output means the electric or mechanical energy made available for use, exclusive of any such energy used in the power production process.
P = W/t
P = 5.5/12*3600
P = 0.0001 W
So, average useful power output of robot is 0.0001 W
t = W/P
W = mgh So t = mgh/P
t = 3500x10x1.8/0.0001
t = 630000000 sec
So, time taken by robot to lift bricks is 630000000 sec
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Answer:
Iron deficiency
Explanation:
or more scientifically explained as decreased hemoglobin levels in your blood but still caused by lack of iron.
Answer:
Dry Cell : It is a primary cell based on Leclanche cell invented by G. Leclanche in 1868. In a primary cell, the electrode reactions cannot be reversed by an external source of electrical energy. In this cell, the cell reaction takes place only once i.e., this cell is not rechargeable. It is.generally used intorched, transistors, radios, calculators, tape recorders etc. It consists of a hollow zinc cylinder which is filled with a paste of NH .
Voltaic Cell Working. The working principle of voltaic cell depends upon the principle that, whenever two dissimilar metals are immersed inside an electrolyte solution, the more reactive metal will have a tendency to dissolve in the electrolyte as positive metal ions, leaving electrons behind on the metal plate.
Answer: Option A; 9.8 m/s^2
Explanation:
When an object is in the air, and there is no air resistance acting on the object, the only force that will act on the object is the gravitational force (on the vertical axis).
Then, if the only force acting on the object is the gravitational force, the acceleration of the object will be equal to the gravitational acceleration.
We know that the gravitational acceleration is equal to:
g = 9.8m/s^2
Then the acceleration on the vertical axis will be equal to:
a(t) = 9.8m/s^2
The correct option is the first one:
A. 9.8 m/s^2