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olga55 [171]
3 years ago
15

11. All objects gain or release heat at the same rate. *

Physics
1 answer:
aleksandrvk [35]3 years ago
5 0

The statement is false.

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The position of a certain airplane during takeoff is given by x=1/2 *bt2, where b = 2.0 m/s2 and t = 0 corresponds to the instan
Serhud [2]

Answer:

1362000 kgm/s

Explanation:

So the total mass combination of the plane and the people inside it is

M = 35000 + 160*65 = 45400 kg

After 15 seconds at an acceleration of 2 m/s2, the plane speed would be

V = 2*15 = 30 m/s

So the magnitude of the plane 15s after brakes are released is

MV = 45400 * 30 = 1362000 kgm/s

5 0
3 years ago
What is the total mechanical energy of a 200 kg roller coaster moving with a velocity of 16 m/s at a height of 18 m above the gr
Travka [436]

Mechanical Energy = PE + KE

PE: mgh = 200 x 9.8 x 18 = 35280

PE: 35280 Joules

KE: 1/2mv^2 = 1/2 x 200 x 16^2 = 25600

KE: 25600 Joules

ME: 35280 + 25600

ME: 60,880J

8 0
3 years ago
A brick is dropped from a big scaffold. What is its velocity after 4.0s?
Flura [38]

The velocity of the brick is 39.2 m/s downward

Explanation:

The motion of the brick is a free fall motion, since the object is affected only by the force of gravity. Therefore, it has a uniformly accelerated motion towards the ground, with constant acceleration of g=9.8 m/s^2.

So, we can find its velocity using the suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the brick in this problem (taking downward as positive direction)

u = 0 (it is dropped from rest)

a=g=9.8 m/s^2

Therefore, its velocity after t = 4.0 s is:

v=0+(9.8)(4.0)=39.2 m/s

Downward, because the sign is positive.

Learn more about free fall motion:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

3 0
3 years ago
Calculate the water pressure in the pipes at the bottom of a high-rise building that is fed by reservoir 60 m above the roof top
yan [13]
P + gh 
14 + (9.8)(60) = 602kPa
5 0
3 years ago
Two identical loudspeakers are driven in phase by the same amplifier. The speakers are positioned a distance of 3.2 m apart. A p
serg [7]

Answer:

f = 735 Hz

Explanation:

given,

Person distance from speakers

r₁ = 4.1 m      r₂ = 4.8 m

Path difference

d = r₂ - r₁ = 4.8 - 4.1 = 0.7 m

For destructive interference

d = \dfrac{n\lambda}{2}

where, n = 1, 3,5..

we know, λ = v/f

d = \dfrac{n v}{2f}

v is the speed of the sound = 343 m/s

f is the frequency

f = \dfrac{n v}{2d}

for n = 1

f = \dfrac{343}{2\times 0.7}

     f = 245 Hz

for n = 3

f = \dfrac{3\times 343}{2\times 0.7}

     f = 735 Hz

Hence,the second lowest frequency of the destructive interference is 735 Hz.

7 0
4 years ago
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