The question is incomplete. The complete question is :
A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a compressed position. The record of time is started when the oscillating mass first passes through the equilibrium position, and the position of the mass at any time is described by x = (4.7 cm)sin[(7.9 rad/s)πt].
Determine the following:
(a) frequency of the motion
(b) period of the motion
(c) amplitude of the motion
(d) first time after t = 0 that the object reaches the position x = 2.6 cm
Solution :
Given equation : x = (4.7 cm)sin[(7.9 rad/s)πt].
Comparing it with the general equation of simple harmonic motion,
x = A sin (ωt + Φ)
A = 4.7 cm
ω = 7.9 π
a). Therefore, frequency, 
= 3.95 Hz
b). The period, 
= 0.253 seconds
c). Amplitude is A = 4.7 cm
d). We have,
x = A sin (ωt + Φ)
Hence, t = 0.0236 seconds.
Answer:
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Explanation:
We want to find the work done and power exerted, let’s start with work first.
We know that the equation for work is: W = F * D. We need to find the force which we can find by using: F = M * A.
Mass: 300kg
Acceleration (using equation from photo): 1.25 m/s^2
(The equation says x but can be used with y values)
If you are confused about how I found the acceleration; I plugged in 2.5 for the final y value, 0 for the initial y value, 0 for the initial velocity and 4 for t squared.
To solve, for acceleration it’s a matter of simple algebra. You can subtract the initial y position and the initial velocity from the final y position because they are 0. This leaves you with 2.5 m = 1/2a * t^2, from here I multiplied 2.5 by 2 to get rid of the 1/2. Now I have 5 = a * t^2. T^2 is just 2 squared, so four. Simply divide 5 by 4, and boom, you get 1.25 m/s^2.
Force = 300 kg * 1.25 m/s^2 = 375 Newtons
So, work = 500 N * 2.5 m = 1000 Joules
Power: W/t
So, Power = 1000 J / 2 seconds = 500 Watts
Hope this helps!
3 because opposites attract
The forms of kinetic energy are motion, heat, sound and light.
So according to your options, I choose D) Sound energy.
