<span>Your equation for the height of the stone at any time is h(t) = -16t2<span> + 128t + 32 .
From your equation, we can tell that you're defining the upward direction as
positive. We can also tell that you threw the stone upward, with an initial speed
as it left your hand of 128 feet per second, about 87 miles per hour ... a mighty toss indeed, and I think there's a man from the Chicago Cubs waiting outside
who'd like to talk to you.
Anyway, When the stone splashes into the water, h(t) = 0 .
</span></span>
<span>-16t²<span> + 128t + 32 = 0</span></span>
Divide each side by -16 :
t² - 8t - 2 = 0
I don't see any easy way to factor the expression on the left,
so I have to use the quadratic formula to solve this equation.
t = 4 plus and minus √18 .
t = +8.24 seconds
t = -0.24 second
Mathematically, both numbers are valid solutions.But when you apply
the equation to a real world situation, only the positive 't' makes sense.
So <u> t = 8.24 seconds</u>.
People interested in careers as Toyota mechanics should consider enrolling in one of the colleges or vocational schools offering the Toyota Motors' T-TEN program. T-TEN stands for Toyota Technician Training and Education Network. This program offers students training options ranging from a one-year professional certificate to a two-year associate's degree. This training may be a requirement for people who want to work for a Toyota dealership. Mechanics can enhance their credentials by completing the requirements of the T-TEN training program and passing the certification tests administered by the National Institute for Automotive Service Excellence (ASE). Automotive Service Technician / Mechanic at Toyota Dealership Salary. Median pay for Auto Mechanics at Toyota Dealership lies in the neighborhood of $16.24 per hour. The income range spans the entire spectrum between $11.48 per hour and $24.49.
Answer:
Explanation:
given, work function of Φ = 2.46 eV.
converting the eV to joule, we have
2.45 * 1.6*10^-19 J
The cutoff wavelength is the wavelength where the incoming light does not have enough energy to free an electron, i.e. all of
the photon’s energy will be channeled into trying overcoming the work function barrier.
It is mathematically given as
Φ = hf
f = Φ/h
f = (2.46 * 1.6*10^-19) / 6.63*10^-34
f = 3.936*10^-19 / 6.63*10^-34
f = 5.94*10^14 Hz as our cut off frequency
λf = c,
λ = c/f
λ = 3*10^8 / 5.94*10^14
λ = 5.05*10^-7
λ = 505 nm as our cut off wavelength
K(max) = hf - Φ
K(max) = hc/λ - Φ
K(max) = [(6.63*10^-34 * 3*10^8) / 181*10^-9] - 3.936*10^-19
K(max) = (1.989*10^-25/181*10^-9) - 3.936*10^-19
K(max) = 1.1*10^-18 - 3.936*10^-19
K(max) = 7.064*10^-19 J or 4.415 eV
V(s) = K(max) / e
V(s) = 4.612 V
Answer:
9517.2 lbm
Explanation:
Electricity consumption = 14000 kWh/year
Fuel consumption = 900 gal/year
Amount of CO₂ produced per gallon = 26.4 lbm/gal
Amount of CO₂ produced per kWh = 1.54 lbm/kWh
Amount of CO₂ produced in one year
Reduction would be
The reduction in the amount of CO₂ produced is 9517.2 lbm
Answer:
N = 3600 N
Explanation:
centripetal acceleration requirement is
ac = v²/r = 20²/50 = 8 m/s²
As the only available acceleration is gravity, centripetal acceleration must come from that,
This makes the "weight" that the road senses and must counteract
N = m(g - ac)
N = 2000(9.8 - 8)
N = 3600 N